MixedJEE Physics · Original learning card10 original chapter questions

Hydrogen-Like Energy Levels

For a one-electron Coulomb system with a heavy nucleus, the total energy of level n is -13.6 Z^2/n^2 eV. The magnitude is the binding energy required to remove the electron from that level.

Why this shows up in the exam

Finding atomic number from level energy · Comparing equal-energy levels in different ions · Locating an orbit from a stated energy

Learn the idea

Bound-state energy is negative and scales as minus Z squared over n squared. Zero energy means the electron is free at infinity. A bound orbit lies below zero; higher n levels are less negative and crowd toward the ionization limit.

🧠 Memory hook: Bound is below zero; bigger n climbs toward zero.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • E_n = -13.6 Z²/n² eV — hydrogen-like total energy
  • binding energy = |E_n| — energy needed to ionize from level n
  • E_infinity = 0 — continuum reference

How to approach it

  1. 1Identify n and Z
  2. 2Calculate the signed level energy
  3. 3Use magnitude only when the question asks binding or ionization energy

Common slip-ups that cost marks

  • •Dropping the negative sign for total energy
  • •Using Z rather than Z squared
  • •Calling the ground-state magnitude the energy itself

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

In hydrogen, an electron transitions from n = 2 to n = 1. Using E_n = -13.6/n^2 eV, find the emitted photon energy.

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