MixedJEE Physics · Original learning card10 original chapter questions

Series Limits, Longest and Shortest Wavelengths

For a series ending at n_f, the longest wavelength uses n_i = n_f + 1, while the shortest wavelength uses n_i approaching infinity. The limit wavenumber is R Z^2/n_f^2.

Why this shows up in the exam

Comparing Lyman and Balmer limits · Finding longest Paschen wavelength · Locating ultraviolet, visible, and infrared series

Learn the idea

Within a series, the first line is longest and the series limit is shortest. The smallest energy drop into a fixed lower level comes from the next level and makes the longest wave. Starting from infinity gives the largest drop and shortest wave.

🧠 Memory hook: Next rung gives longest; infinity gives shortest.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • 1/lambda_max = R Z² (1/n_f² - 1/(n_f+1)²) — longest wavelength, first line of a series
  • 1/lambda_min = R Z²/n_f² — shortest wavelength, series limit
  • nu_limit = c R Z²/n_f² — series-limit frequency

How to approach it

  1. 1Fix n_f from the series
  2. 2Choose n_i = n_f + 1 or infinity
  3. 3Invert only after calculating the wavenumber

Common slip-ups that cost marks

  • •Calling the first line the shortest
  • •Substituting n_i = 0 for the limit
  • •Comparing wavelengths by comparing wavenumbers in the same direction

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

In hydrogen, an electron transitions from n = 2 to n = 1. Using E_n = -13.6/n^2 eV, find the emitted photon energy.

Take a timed JEE Physics sectional mock