MixedJEE Physics · Original learning card10 original chapter questions

Nuclear Force, Short Range, and Saturation

The residual strong interaction between nucleons is attractive over typical nuclear separations, strongly repulsive at very short separation, approximately charge independent, and effective over only a few femtometres. Its short range produces saturation of binding.

Why this shows up in the exam

Explaining the binding-energy plateau · Contrasting nuclear and electrostatic forces · Reasoning about nuclear density and stability

Learn the idea

The strong nuclear force is short-ranged and saturating, which explains nearly constant density and binding per nucleon. A nucleon strongly interacts mainly with nearby nucleons, not equally with every nucleon in the nucleus. That local neighborhood produces saturation: adding distant nucleons does not multiply each nucleon's binding without limit.

🧠 Memory hook: Strong but short: a nucleon mainly binds to near neighbors.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • range approximately 1 to 2 fm — order-of-magnitude range over which the residual nuclear force is significant
  • B/A approximately constant for 30 < A < 170 — saturation trend, not an exact law for every nuclide

How to approach it

  1. 1Identify whether the statement concerns range, strength, or charge dependence
  2. 2Use saturation to explain a plateau, not every local variation
  3. 3Reject explanations that require all nucleon pairs to interact equally

Common slip-ups that cost marks

  • •Calling the nuclear force long-ranged
  • •Assuming it is purely attractive at every separation
  • •Equating residual nuclear force with gravity or Coulomb force

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

In hydrogen, an electron transitions from n = 2 to n = 1. Using E_n = -13.6/n^2 eV, find the emitted photon energy.

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