Exam level7 past questions

Coordination Geometry and Hybridization

The geometry of coordination complexes (octahedral, tetrahedral, square planar, etc.) is determined by the hybridization of the central metal's orbitals and the nature of the ligands.

Why this shows up in the exam

You will need to predict or deduce the geometry and hybridization of complexes in exams.

How NEET tests this

Direct recall · 3 QsApplication · 2 QsStatement analysis

Practise it

These are real questions from past NEET papers that test this exact idea.

Question 1 of 7

Match List I with List II : List-I (Complex/ion) A. [Pt(Cl₂)(NH₃)₂] B. [Co(NH₃)₆]Cl₃ C. [NiCl₄]²⁻ D. [Fe(CO)₅] List-II (Shape/geometry) I. Octahedral II. Trigonal bipyramidal III. Square planar IV. Tetrahedral Choose the correct answer from the options given below:

Push further

More challenging

12 harder questions built from the past papers above — a step up in difficulty, with distractors designed so you can't get there by elimination. Written and checked by our reviewers, not from a real paper.

Question 1 of 12

Which of the following statements correctly describes the hybridization and geometry of the complex ion [Fe(CN)₆]³⁻?