MixedJEE Physics · Original learning card10 original chapter questions

Flux-Time Graphs and Average EMF

For one turn, emf is the negative slope of the Phi-t graph. For N turns, multiply the slope by N. Corners indicate sudden changes of emf in an idealized graph.

Why this shows up in the exam

Reading generator waveforms · Pulse transformers · Inductive sensor signals

Learn the idea

The slope of a flux-time graph gives induced emf. On a flux-versus-time graph, a steep section means rapid change and therefore large emf. A horizontal section means no change and zero emf.

🧠 Memory hook: Flux slope becomes emf; emf area becomes flux change.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • emf = -N slope(Phi-t) — signed emf from a flux-time graph
  • area under emf-t = -N Delta Phi — flux change from an emf-time graph

How to approach it

  1. 1Mark time intervals
  2. 2Calculate each slope
  3. 3Apply the minus sign only after choosing polarity

Common slip-ups that cost marks

  • •Reading graph height instead of slope
  • •Ignoring axis scales
  • •Forgetting that constant nonzero flux still gives zero emf

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A conducting rod of length 2 m moves at 3 m/s perpendicular to a 4 T magnetic field. Find the motional emf.

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