MixedJEE Physics · Original learning card10 original chapter questions

Motional EMF in a Moving Conductor

For a straight rod of length l moving with velocity v in a uniform field B, the simple Blv form applies only when B, l, and v are mutually perpendicular.

Why this shows up in the exam

Rail generators · Flow meters · Aircraft wing voltage in Earth's field

Learn the idea

Charges in a moving conductor feel magnetic force and separate, creating emf. As a rod cuts magnetic field lines, positive and negative charges are pushed toward opposite ends. Their separation creates a voltage across the rod.

🧠 Memory hook: B-l-v: mutually perpendicular gives Blv.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • emf = B l v — perpendicular rod, field, and velocity
  • F_m = q(v x B) — magnetic force that separates charge

How to approach it

  1. 1Draw v, B, and the rod
  2. 2Use v cross B for positive charge
  3. 3Apply Blv if perpendicular

Common slip-ups that cost marks

  • •Using Blv without checking geometry
  • •Confusing rod speed with charge drift speed
  • •Choosing polarity without using v cross B

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A conducting rod of length 2 m moves at 3 m/s perpendicular to a 4 T magnetic field. Find the motional emf.

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