MixedJEE Physics · Original learning card10 original chapter questions

Rotating Coil and AC Generator

For a coil of N turns and area A rotating at angular speed omega in uniform B, the peak emf is N B A omega.

Why this shows up in the exam

Power-station alternators · Bicycle dynamos · Turbine generators

Learn the idea

A rotating coil converts mechanical rotation into sinusoidal emf. Rotation continuously changes the angle between the coil's area vector and magnetic field. The flux is cosine-shaped, so its time derivative, the emf, is sine-shaped.

🧠 Memory hook: Flux is cosine; emf is its derivative sine.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • Phi = N B A cos(omega t) — flux linkage of a rotating coil
  • emf = N B A omega sin(omega t) — generated emf
  • emf₀ = N B A omega — peak emf

How to approach it

  1. 1Write flux first
  2. 2Differentiate
  3. 3Check the quarter-cycle phase difference

Common slip-ups that cost marks

  • •Confusing angular speed with frequency
  • •Forgetting N
  • •Assuming maximum flux and maximum emf occur together

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A conducting rod of length 2 m moves at 3 m/s perpendicular to a 4 T magnetic field. Find the motional emf.

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