MixedJEE Physics · Original learning card10 original chapter questions

Induced Charge and Energy Conservation

With constant circuit resistance and negligible self-inductance, integrating I = emf/R gives the magnitude of total charge as N times flux change divided by R.

Why this shows up in the exam

Ballistic galvanometers · Magnetic-flux measurement · Generator braking calculations

Learn the idea

Total induced charge depends on flux change and resistance, not on how quickly the change occurs. A faster change gives larger emf for less time; a slower change gives smaller emf for more time. When integrated, both transfer the same charge if flux change and resistance are unchanged.

🧠 Memory hook: Emf cares about speed; total charge cares about total flux change.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • q = N |Delta Phi|/R — total induced charge for constant R
  • mechanical work = electrical energy + change in stored field energy — energy accounting in induction

How to approach it

  1. 1Find total flux change
  2. 2Check that R is constant
  3. 3Use energy conservation for force or heat

Common slip-ups that cost marks

  • •Putting time into q = N Delta Phi/R
  • •Using the formula when resistance varies strongly
  • •Ignoring magnetic energy stored in an inductor

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A conducting rod of length 2 m moves at 3 m/s perpendicular to a 4 T magnetic field. Find the motional emf.

Take a timed JEE Physics sectional mock