Exam level3 past questions

Energy, momentum, and radiation pressure of electromagnetic waves

Electromagnetic waves transport energy and momentum, exerting radiation pressure and force on surfaces, with quantifiable energy density and intensity.

Why this shows up in the exam

NEET includes questions on how electromagnetic waves interact with matter and how to calculate related physical quantities.

How NEET tests this

Application · 2 QsStatement analysisNumerical

Learn the idea

Electromagnetic waves carry energy and momentum; when they strike a surface they exert a radiation pressure that produces a force.

🧠 Memory hook: I‑c‑P‑2P (Intensity → c → Pressure, double for perfect reflector)

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • Intensity I is the energy flux (energy per unit area per unit time) of the wave
  • Radiation pressure on a perfectly absorbing surface is I/c and on a perfectly reflecting surface is 2I/c
  • Momentum associated with radiation of energy E is E/c
  • Electric and magnetic fields store equal energy, so their contributions to intensity are in the ratio 1:1
  • Force on a surface equals radiation pressure multiplied by the illuminated area

How to approach it

  1. 1Identify the required quantity and the nature of the surface (absorbing or reflecting)
  2. 2Write the NCERT relation appropriate to that situation (P=I/c or P=2I/c, p=E/c, F=P·A)
  3. 3Insert the given numbers, keep units consistent, and compute the answer

Worked example — watch it click

Light with an energy flux of 25 × 10⁴ W m⁻² falls on a perfectly reflecting surface at normal incidence. If the surface area is 15 cm², the average force exerted on the surface is:

  • A)1.20 × 10⁻⁶ N
  • B)3.0 × 10⁻⁶ N
  • C)1.25 x 10⁻⁶ N
  • ✅2.50 × 10⁻⁶ N

The concept behind this problem

The example forces you to apply the NCERT formula P=2I/c for a reflecting surface and then use F=P·A, directly testing the idea that EM waves transfer momentum and exert pressure.

Step by step

  1. 1Energy flux (intensity) I = 25×10⁴ W/m², Area A = 15 cm² = 15×10⁻⁴ m².
  2. 2For perfect reflection at normal incidence, radiation pressure P = 2I/c.
  3. 3Force F = P×A = (2I/c)×A = (2×25×10⁴×15×10⁻⁴)/(3×10⁸) = (2×25×15×10⁰)/(3×10⁸) = 750/(3×10⁸) = 2.5×10⁻⁶ N.

Watch out

Using I/c instead of 2I/c for a reflecting surface cuts the force in half.

Common slip-ups that cost marks

  • •Missing the factor of two for a perfectly reflecting surface
  • •Confusing intensity with energy density; intensity is power per unit area, not stored energy

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Practise it

These are real questions from past NEET papers that test this exact idea.

Question 1 of 3NEET 2014

Light with an energy flux of 25 × 10⁴ W m⁻² falls on a perfectly reflecting surface at normal incidence. If the surface area is 15 cm², the average force exerted on the surface is:

Push further

More challenging

13 harder questions built from the past papers above — a step up in difficulty, with distractors designed so you can't get there by elimination. Written and checked by our reviewers, not from a real paper.

Question 1 of 13

An electromagnetic wave propagates through a vacuum. If the average energy density due to its electric field is 2.0 x 10⁻⁸ J/m³, what is the average energy density due to its magnetic field?

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