MixedJEE Physics · Original learning card10 original chapter questions

Uniformly Charged Solid Sphere

For volume density rho, E_inside = rho r/(3 epsilon_0). For r >= R, E = kQ/r^2. These results require spherical symmetry and uniform density.

Why this shows up in the exam

Solid-sphere field graphs · Comparing fields of spheres · Finding force inside a uniform sphere

Learn the idea

Inside a uniform nonconducting sphere E grows linearly with r; outside it falls as 1/r². A Gaussian sphere encloses a fraction r³/R³ of the total charge, while its area grows as r², leaving an interior field proportional to r.

🧠 Memory hook: Uniform solid sphere: linear up, inverse-square down.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • E(r<R) = rho r/(3 epsilon₀) — interior field
  • E(r>=R) = kQ/r² — exterior field
  • Q_enclosed = (4/3) pi r³ rho — interior enclosed charge

How to approach it

  1. 1Check whether r is inside or outside
  2. 2Compute enclosed charge
  3. 3Apply Gauss and verify continuity at the surface

Common slip-ups that cost marks

  • •Using the full charge for an interior point
  • •Calling the sphere conducting
  • •Missing continuity of E at r = R

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

Two point charges 1 microC and 2 microC are 1 m apart in vacuum. Take k = 9 x 10^9 SI. Find the force magnitude.

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