MixedJEE Physics · Original learning card10 original chapter questions

Partial Dielectric by Area

Neglecting fringing, regions occupying disjoint plate areas with the same separation and common plate potentials form parallel capacitances.

Why this shows up in the exam

half-filled plates · liquid rising between vertical plates · slabs inserted sideways

Learn the idea

Side-by-side dielectric regions act as parallel capacitors. If dielectric covers only part of the plate area through the full gap, each area strip sees the same voltage, so their capacitances add in parallel.

🧠 Memory hook: Split area means parallel.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • C = (epsilon₀/d) sum(K_i A_i) — area partitions spanning the gap
  • C(x)=epsilon₀[K A_filled(x)+A_air(x)]/d — partially inserted slab by area

How to approach it

  1. 1Sketch field direction
  2. 2Partition area perpendicular to the plates
  3. 3Add regional capacitances

Common slip-ups that cost marks

  • •Treating side-by-side regions as series
  • •Using total area for every region
  • •Ignoring changing overlap area

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

Two point charges 1 microC and 2 microC are 1 m apart in vacuum. Take k = 9 x 10^9 SI. Find the force magnitude.

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