MixedJEE Physics · Original learning card5 original chapter questions

Potential and Field Graphs

For a finite nonsingular spherical density, V(r) is continuous at the surface and g_r=-dV/dr; for a uniform solid sphere the interior potential is quadratic in r and joins -GM/r smoothly at r=R.

Why this shows up in the exam

Selecting potential graphs · Finding zero-field locations · Checking boundary continuity

Learn the idea

The field is minus the slope of V(r), while potential remains continuous across ordinary mass boundaries. A graph encodes both force direction and strength: steep potential means strong field, and a flat potential means zero field.

🧠 Memory hook: Read field from negative slope, not graph height.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • g_r = -dV/dr — radial field from potential-curve slope
  • V_uniform(r<=R) = -GM(3R²-r²)/(2R³) — potential inside a uniform solid sphere

How to approach it

  1. 1Mark centre, surface, and infinity
  2. 2Check continuity and limiting values
  3. 3Use negative slope to infer field

Common slip-ups that cost marks

  • •Making V discontinuous at a surface
  • •Calling zero potential zero field
  • •Ignoring the sign of graph slope

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A satellite moves in a circular orbit where GM = 4 x 10^14 m^3/s^2 and orbital radius is 2 x 10^6 m. Find its orbital speed.

Take a timed JEE Physics sectional mock