MixedJEE Physics · Original learning card5 original chapter questions

Escape Speed and Escape Energy

Ignoring drag and other bodies, setting K+U=0 at launch radius r gives v_e=sqrt(2GM/r); the required kinetic energy from rest is GMm/r and v_e=sqrt(2) v_c at the same radius.

Why this shows up in the exam

Planet escape-speed scaling · Minimum energy to infinity · Multi-source escape using total potential

Learn the idea

Escape is the zero-total-energy threshold, giving v_e=sqrt(2GM/r) from distance r. At the minimum escape speed an object reaches infinity with zero remaining speed; it need not keep accelerating outward.

🧠 Memory hook: Escape sets final speed at infinity to zero.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • v_e = sqrt(2GM/r) — escape speed from centre distance r
  • K_escape = GMm/r — minimum launch kinetic energy from rest
  • v_e = sqrt(2) v_c — relation to circular speed at the same radius

How to approach it

  1. 1Choose launch point and all gravitational sources
  2. 2Set final total energy to zero
  3. 3Solve for speed or energy and test units

Common slip-ups that cost marks

  • •Using surface formula at altitude
  • •Assuming escape speed depends on projectile mass
  • •Adding separate escape speeds instead of potentials

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A satellite moves in a circular orbit where GM = 4 x 10^14 m^3/s^2 and orbital radius is 2 x 10^6 m. Find its orbital speed.

Take a timed JEE Physics sectional mock