MixedJEE Physics · Original learning card5 original chapter questions

Geostationary and Relative Satellite Motion

A geostationary orbit has T equal to Earth's sidereal rotation period in a circular prograde equatorial orbit; observed conjunction rates use relative angular speed omega_rel=|omega1-omega2| for the same sense and omega1+omega2 for opposite senses.

Why this shows up in the exam

Geostationary feasibility · Opposite-direction satellite timing · Relative observations from an orbit

Learn the idea

A geostationary satellite must be prograde, equatorial, circular, and have Earth's sidereal rotation period. Matching only the period is not enough to hover over one place; orbit direction and plane must also match Earth's rotation.

🧠 Memory hook: Hovering needs period, plane, direction, and circularity.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • T_geo = T_rotation — period condition for a geostationary orbit
  • omega_rel = |omega1 - omega2| or omega1 + omega2 — relative angular rate for same or opposite senses
  • T_rel = 2 pi/omega_rel — relative recurrence period

How to approach it

  1. 1Check all four geostationary conditions
  2. 2Find each angular speed in one frame
  3. 3Combine signs before converting to relative period

Common slip-ups that cost marks

  • •Calling any 24-hour orbit geostationary
  • •Using solar day without checking convention
  • •Subtracting angular speeds for opposite directions

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A satellite moves in a circular orbit where GM = 4 x 10^14 m^3/s^2 and orbital radius is 2 x 10^6 m. Find its orbital speed.

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