MixedJEE Physics · Original learning card10 original chapter questions

Position, Path Length, and Displacement

For one-dimensional motion, displacement over an interval is Delta x = x_f - x_i and may be positive, negative, or zero. Distance is the non-negative path length, so distance is always at least |Delta x|.

Why this shows up in the exam

Trips with reversals · Circular-path questions reduced to endpoint separation · Checking whether a particle returned to its start

Learn the idea

Position locates a particle, path length counts its route, and displacement compares only the endpoints. An odometer remembers every part of a journey, while displacement acts like an arrow drawn directly from the starting point to the finishing point. Returning to the start can therefore give a large distance but zero displacement.

🧠 Memory hook: Distance follows the road; displacement joins the endpoints.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • Delta x = x_f - x_i — signed displacement from initial to final coordinate
  • distance >= |Delta x| — path length cannot be smaller than endpoint separation

How to approach it

  1. 1Mark initial and final coordinates
  2. 2Compute signed endpoint change
  3. 3Add every path segment separately only when distance is asked

Common slip-ups that cost marks

  • •Treating distance as signed
  • •Using path length for displacement
  • •Forgetting that zero displacement need not mean no motion

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A particle has initial speed 2 m/s and constant acceleration 3 m/s^2 for 4 s. What distance does it cover?

Take a timed JEE Physics sectional mock