MixedJEE Physics · Original learning card5 original chapter questions

Spring Force and Coupled Motion

For an ideal spring operating within its linear elastic limit, the restoring force is F_s = -kx, where x is measured from the natural length, and the stored elastic potential energy is U_s = kx^2/2.

Why this shows up in the exam

Spring calibration · Coupled blocks · Maximum extension

Learn the idea

An ideal spring exerts -kx and stores kx squared over two. Spring deformation couples blocks and pulleys; maximum extension need not mean zero acceleration.

🧠 Memory hook: Force is kx; energy is half kx squared.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • F_s = -k x — Hooke law
  • U_s = (1/2)k x² — spring energy
  • Delta K+Delta U_g+Delta U_s=0 — conservative balance

How to approach it

  1. 1Define deformation
  2. 2Write constraints
  3. 3Choose force or energy method

Common slip-ups that cost marks

  • •Using kx as energy
  • •Zero acceleration at turning point
  • •Ignoring pulley ratios

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg block moves on a horizontal rough surface with coefficient of kinetic friction 0.2. A horizontal force of 10 N acts on it. Take g = 10 m/s^2. What is its acceleration?

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