MixedJEE Physics · Original learning card10 original chapter questions

Magnetic Dipole Moment of a Current Loop

For a planar N-turn loop carrying steady current I, the magnetic dipole moment is the axial vector m = NIA n-hat, where n-hat is fixed by curling the right-hand fingers with the current.

Why this shows up in the exam

Finding the moment of coils and shaped current loops · Comparing electromagnets with bar magnets · Calculating torque and energy of a loop in a field

Learn the idea

A current loop behaves as a magnetic dipole with moment equal to current times vector area. Current circulating around a loop produces a directional magnetic effect. More current, more turns, or a larger loop area makes the dipole stronger; the right-hand rule gives its direction.

🧠 Memory hook: Current times area, with the thumb through the loop.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • m = N I A — magnitude of the magnetic moment of a planar N-turn loop
  • m_vector = N I A n_hat — vector form with direction from the right-hand rule
  • m = I L²/(4 pi) — moment when a wire of length L forms one circular loop

How to approach it

  1. 1Find the area enclosed by one turn
  2. 2Multiply by current and number of turns
  3. 3Use the right-hand rule before applying vector formulas

Common slip-ups that cost marks

  • •Using circumference instead of enclosed area
  • •Forgetting the number of turns
  • •Taking the loop plane, rather than its normal, as the moment direction

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A charge of 2 microC moves perpendicular to a 3 T magnetic field at 4 x 10^5 m/s. Find the magnetic force.

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