MixedJEE Physics · Original learning card10 original chapter questions

Torque on a Magnetic Dipole

A magnetic dipole m in a uniform field B experiences torque tau = m cross B, of magnitude mB sin theta. The torque is zero when parallel or antiparallel and maximum at 90 degrees.

Why this shows up in the exam

Current-coil rotation · Compass alignment · Finding an unknown dipole moment from measured torque

Learn the idea

A uniform magnetic field turns a dipole toward alignment without giving it net force. The field pulls opposite sides of a current loop in opposite directions. In a uniform field these forces cancel as a pair but form a turning effect that aligns the dipole moment with the field.

🧠 Memory hook: Uniform B turns a dipole; it does not pull the whole dipole.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • tau_vector = m_vector cross B_vector — direction and magnitude of dipole torque
  • tau = m B sin(theta) — torque magnitude for angle theta between m and B
  • F_net = 0 in uniform B — opposite forces cancel for an ideal dipole in a uniform field

How to approach it

  1. 1Draw m normal to the loop
  2. 2Measure theta between m and B
  3. 3Use the cross product for direction and mB sin theta for magnitude

Common slip-ups that cost marks

  • •Using cos theta in the torque
  • •Using the loop plane angle instead of the moment angle
  • •Assigning a net force in a uniform field

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A charge of 2 microC moves perpendicular to a 3 T magnetic field at 4 x 10^5 m/s. Find the magnetic force.

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