MixedJEE Physics · Original learning card10 original chapter questions

Centre of Mass of Continuous Bodies

For a continuous mass distribution, the centre of mass is defined by integrating position against the mass element and dividing by total mass, with symmetry used only when the density and geometry justify it.

Why this shows up in the exam

Finding centroids of rods, plates, cones, and solids · Replacing extended weight by an equivalent point in uniform gravity · Using symmetry to locate balance points

Learn the idea

A continuous body's centre of mass is the density-weighted average over all of its material. A continuous body's centre of mass is the density-weighted average over all of its material. Start from a clear axis, origin, body, and reference frame; the geometry and constraints then decide which rotational law is safe to use.

🧠 Memory hook: Integrate position weighted by how much mass is there.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • r_cm = (1/M) integral r dm — General centre-of-mass definition for a continuous body.
  • dm = lambda dl = sigma dA = rho dV — Mass element chosen for line, area, or volume density.

How to approach it

  1. 1Exploit valid symmetry before integrating
  2. 2Write the correct mass element and limits
  3. 3Compute the first moment and verify dimensions and location

Common slip-ups that cost marks

  • •Using geometric centre for a nonuniform body
  • •Choosing an inconsistent density element
  • •Forgetting to divide the first moment by total mass

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

Masses 1 kg and 3 kg lie at x = 0 and x = 4 m. Find the x-coordinate of their centre of mass.

Take a timed JEE Physics sectional mock