MixedJEE Physics · Original learning card10 original chapter questions

Angular Momentum of a Particle

The angular momentum of a particle about origin O is L_O = r cross p, so its magnitude is mvr_perpendicular and can change even at constant speed if the direction or line of motion changes.

Why this shows up in the exam

Particles passing an offset point · Orbital motion under central forces · Choosing an origin for collision analysis

Learn the idea

A particle's angular momentum depends on its linear momentum and its perpendicular offset from the origin. A particle's angular momentum depends on its linear momentum and its perpendicular offset from the origin. Start from a clear axis, origin, body, and reference frame; the geometry and constraints then decide which rotational law is safe to use.

🧠 Memory hook: Angular momentum is momentum times perpendicular miss distance.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • L_O = r cross p — Particle angular momentum about O.
  • |L_O| = m v b — Magnitude for impact parameter b relative to O.
  • tau_O = dL_O/dt — Torque-angular-momentum relation in an inertial frame.

How to approach it

  1. 1Name the origin
  2. 2Find r and momentum at the same instant
  3. 3Use the cross product or impact parameter with sign

Common slip-ups that cost marks

  • •Using radial distance instead of perpendicular distance
  • •Assuming L is origin-independent
  • •Dropping the cross-product direction

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

Masses 1 kg and 3 kg lie at x = 0 and x = 4 m. Find the x-coordinate of their centre of mass.

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