MixedJEE Physics · Original learning card10 original chapter questions

Radius of Gyration

The radius of gyration k of a body about a specified axis is defined by I = M k squared, so k is the root-mean-square perpendicular distance of mass from that axis.

Why this shows up in the exam

Comparing compact and spread-out bodies · Rewriting pendulum and rolling formulas · Designing flywheel mass distributions

Learn the idea

Radius of gyration is the equivalent distance at which all mass could reproduce the same inertia. Radius of gyration is the equivalent distance at which all mass could reproduce the same inertia. Start from a clear axis, origin, body, and reference frame; the geometry and constraints then decide which rotational law is safe to use.

🧠 Memory hook: Radius of gyration is the RMS mass distance from the axis.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • k = sqrt(I/M) — Radius of gyration about the same axis used for I.
  • k² = (1/M) integral r_perp² dm — Mean squared mass distance from the axis.

How to approach it

  1. 1Compute or identify I about the named axis
  2. 2Divide by total mass
  3. 3Take the positive square root and attach length units

Common slip-ups that cost marks

  • •Treating k as the geometric radius
  • •Using total mass inconsistent with I
  • •Comparing k values about different axes

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

Masses 1 kg and 3 kg lie at x = 0 and x = 4 m. Find the x-coordinate of their centre of mass.

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