MixedJEE Physics · Original learning card10 original chapter questions

Refractive Index, Speed, Frequency and Wavelength

For a monochromatic wave in a transparent nondispersive approximation, n = c/v and lambda_medium = lambda_0/n; frequency is continuous across the interface.

Why this shows up in the exam

Material identification · Optical-path calculations · Wavelength selection in media

Learn the idea

Refractive index compares light speed in vacuum with its phase speed in a medium. Light slows and its wavelength shortens in a higher-index medium, while its frequency remains fixed at a stationary boundary.

🧠 Memory hook: Boundary keeps frequency; speed and wavelength change together.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • n = c/v — absolute refractive index
  • lambda2/lambda1 = v2/v1 = n1/n2 — frequency unchanged at the boundary

How to approach it

  1. 1Write n = c/v for each medium
  2. 2Keep frequency common
  3. 3Scale wavelength with speed

Common slip-ups that cost marks

  • •Changing frequency on refraction
  • •Inverting the n-speed relation
  • •Using vacuum wavelength inside a medium

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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