MixedJEE Physics · Original learning card10 original chapter questions

Escape Cone and Visibility Through a Surface

For a point at depth h in higher-index medium, the escape-cone half-angle is C and the surface-circle radius is h tan C for a plane boundary.

Why this shows up in the exam

Underwater viewing · Submerged-light design · Aquarium illumination

Learn the idea

Only rays inside an interface's escape cone can leave a higher-index medium. A submerged observer sees the outside world compressed into a cone, while an underwater source illuminates only a finite patch above.

🧠 Memory hook: The critical angle is the rim of the escape window.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • sin(C) = n_out/n_in — escape-cone half-angle
  • radius = h tan(C) — circular patch at a plane surface

How to approach it

  1. 1Locate the source or observer
  2. 2Draw the limiting ray at C
  3. 3Use right-triangle geometry at the surface

Common slip-ups that cost marks

  • •Using the full cone angle as C
  • •Using apparent depth in the geometric radius
  • •Forgetting which side contains the source

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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