MixedJEE Physics · Original learning card10 original chapter questions

Lens Maker's Formula

For a thin lens in air, 1/f = (n-1)(1/R1-1/R2). In a medium replace n by the relative index n_lens/n_medium.

Why this shows up in the exam

Spectacle-lens manufacture · Camera-lens design · Index measurement

Learn the idea

A lens's focal length is set by its surface curvatures and refractive index relative to its medium. Stronger curvature and a larger index contrast bend rays more and therefore increase optical power.

🧠 Memory hook: Lens power equals index contrast times curvature difference.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • 1/f = (n-1)(1/R1-1/R2) — thin lens in air
  • 1/f_m = (n_l/n_m-1)(1/R1-1/R2) — thin lens immersed in medium n_m

How to approach it

  1. 1Mark light direction and curvature centres
  2. 2Assign signed R1 and R2
  3. 3Use relative index for the surrounding medium

Common slip-ups that cost marks

  • •Using unsigned radii
  • •Using absolute lens index after immersion
  • •Applying the formula to a thick lens without qualification

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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