MixedJEE Physics · Original learning card10 original chapter questions

Minimum Deviation and Prism Refractive Index

For a prism in air at minimum deviation, i=e, r1=r2=A/2 and n = sin[(A+delta_m)/2]/sin(A/2).

Why this shows up in the exam

Prism spectrometers · Material index measurement · Wavelength calibration

Learn the idea

At minimum deviation the prism path is symmetric, allowing refractive index to be found directly. The least-deviated ray enters and leaves at equal angles, so the internal ray splits the prism angle equally.

🧠 Memory hook: Minimum deviation means a symmetric path.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • n = sin((A+delta_m)/2)/sin(A/2) — prism index in air at minimum deviation
  • i = e; r1 = r2 = A/2 — symmetric minimum-deviation path

How to approach it

  1. 1Confirm minimum-deviation wording
  2. 2Set the symmetric angles
  3. 3Apply the sine-ratio formula

Common slip-ups that cost marks

  • •Setting i=A/2 instead of r=A/2
  • •Using ordinary deviation in the minimum formula
  • •Ignoring the external medium

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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