MixedJEE Physics · Original learning card10 original chapter questions

Prism Combinations and Achromatic/Direct-Vision Conditions

For thin oppositely oriented prisms, net mean deviation and net angular dispersion are signed sums. Achromatism requires omega1 delta1 + omega2 delta2 = 0.

Why this shows up in the exam

Direct-vision spectroscopes · Achromatic prism pairs · Beam steering with colour control

Learn the idea

Two prisms can be oriented so their mean deviations or their colour dispersions cancel selectively. Oppositely placed prisms act like angular vectors: one can undo steering while retaining colour spread, or undo colour spread while retaining steering.

🧠 Memory hook: Choose what cancels: mean bend or colour spread.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • delta_net = sum(s_j (n_j-1)A_j) — signed thin-prism mean deviation
  • sum(s_j (n_v-n_r)_j A_j) = 0 — zero net angular dispersion

How to approach it

  1. 1Assign an orientation sign to each prism
  2. 2Write mean-deviation and dispersion sums separately
  3. 3Apply the requested zero condition

Common slip-ups that cost marks

  • •Using the same sign for opposite prisms
  • •Equating achromatism with zero deviation
  • •Using dispersive power without mean deviation

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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