MixedJEE Physics · Original learning card10 original chapter questions

Compound Microscope and Resolution

For normal adjustment in the standard long-tube approximation, M = (L/f_o)(D/f_e) in magnitude. Resolution improves with shorter wavelength and larger numerical aperture.

Why this shows up in the exam

Biological microscopy · Metallurgical inspection · Electron-microscope comparison

Learn the idea

A compound microscope multiplies the objective's linear magnification by the eyepiece's angular magnification. The short-focus objective first makes a large real intermediate image, then the eyepiece acts as a magnifier.

🧠 Memory hook: Objective enlarges first; eyepiece enlarges the angle.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • |M| approximately (L/f_o)(D/f_e) — normal adjustment and L much larger than f_o
  • d_min approximately 0.61 lambda/NA — diffraction-limited lateral resolution

How to approach it

  1. 1Find the objective image or use the stated approximation
  2. 2Compute eyepiece angular magnification
  3. 3Multiply magnitudes and treat resolution separately

Common slip-ups that cost marks

  • •Adding component magnifications
  • •Using tube length as exact objective image distance without approximation
  • •Equating magnification with resolving power

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

Take a timed JEE Physics sectional mock