MixedJEE Physics · Original learning card10 original chapter questions

YDSE Path Difference and Fringe Positions

For slit separation d and observation angle theta, the far-field path difference is d sin(theta). Bright fringes satisfy m lambda and dark fringes satisfy (m+1/2) lambda. Under the small-angle approximation, y is approximately D theta.

Why this shows up in the exam

Measuring wavelength · Demonstrating wave nature of light · Calibrating small separations

Learn the idea

Young's two slits convert path difference into regularly placed bright and dark fringes. Each slit acts like a synchronized ripple source. Moving across the distant screen changes one route a little more than the other, alternating reinforcement and cancellation.

🧠 Memory hook: Path difference decides; screen position only translates it.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • Delta = d sin(theta) approximately d y/D — YDSE path difference
  • y_bright = m lambda D/d — small-angle bright-fringe position
  • y_dark = (m + 1/2) lambda D/d — small-angle dark-fringe position

How to approach it

  1. 1Write the exact path condition first
  2. 2Choose bright or dark order carefully
  3. 3Use y approximately D sin(theta) only when justified

Common slip-ups that cost marks

  • •Using d/D instead of D/d
  • •Counting the central bright as order one
  • •Using small-angle formulas at large angles without checking

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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