MixedJEE Physics · Original learning card10 original chapter questions

Brewster's Law and Polarization by Reflection

For incidence from medium n1 into n2, Brewster angle i_B satisfies tan(i_B)=n2/n1. At this angle i_B+r=90 degrees, and the reflected light is polarized perpendicular to the plane of incidence.

Why this shows up in the exam

Polarizing sunglasses · Reducing reflection in imaging · Measuring refractive index

Learn the idea

At Brewster incidence, reflected light is linearly polarized and reflected and refracted rays are perpendicular. At one special tilt, the reflected electric-field component in the plane of incidence vanishes, leaving only the perpendicular component.

🧠 Memory hook: Brewster makes reflected and refracted rays a right angle.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • tan(i_B) = n2/n1 — Brewster's law
  • i_B + r = 90 degrees — perpendicular reflected and refracted rays
  • n1 sin(i_B) = n2 sin(r) — Snell's law at the interface

How to approach it

  1. 1Identify incident and transmitted media
  2. 2Use tan(i_B)=n2/n1
  3. 3Use i_B+r=90 degrees for direction questions

Common slip-ups that cost marks

  • •Using n1/n2 instead of n2/n1
  • •Saying reflected polarization lies in the incidence plane
  • •Using the critical-angle relation at Brewster incidence

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A real object is placed 30 cm from a converging lens of focal length 10 cm. Find the real image distance.

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