MixedJEE Physics · Original learning card10 original chapter questions

Period Scaling, Clocks, and Measurement

Oscillator periods scale as T proportional to sqrt(inertia/restoring coefficient); for a simple pendulum T proportional to sqrt(l/g), enabling clock-rate and graph analysis.

Why this shows up in the exam

Pendulum clocks at altitude or temperature · Experimental L versus T squared plots · Mass, length, stiffness, or planet scaling

Learn the idea

Period ratios expose how length, gravity, mass, stiffness, and thermal expansion change an oscillator. Most comparison questions become simple after identifying what changed and taking a ratio, avoiding repeated calculation of constants.

🧠 Memory hook: Period is the square root of inertia over restoring strength.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • T2/T1 = sqrt((I2/K2)/(I1/K1)) — general period ratio from inertia and restoring coefficient
  • Delta T/T approximately equals 0.5 Delta l/l - 0.5 Delta g/g — small fractional change for a pendulum
  • L = g T²/(4 pi²) — linear L versus T squared experimental relation

How to approach it

  1. 1Write the governing proportionality
  2. 2List fixed and changed quantities
  3. 3Form the ratio and interpret whether the clock gains or loses

Common slip-ups that cost marks

  • •Reversing a square-root ratio
  • •Treating clock gain as period gain
  • •Changing mass in an ideal simple-pendulum formula

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A mass of 1 kg is attached to a spring of force constant 100 N/m. Find the angular frequency of small oscillations.

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