Exam level15 past questions

Dimensional analysis and formulas

Understand dimensional formulas, the principle of homogeneity, dimensional consistency, and how to use dimensional analysis to check equations and derive relationships.

Why this shows up in the exam

NEET often asks you to verify equations, derive formulas, and analyze physical relationships using dimensional analysis.

How NEET tests this

Application · 9 QsDirect recall · 5 QsNumerical · 2 Qs

Learn the idea

Dimensional analysis expresses any physical quantity as a product of powers of the three base dimensions M, L and T. The single insight is that only quantities with identical dimensions can be added or subtracted, so every physically correct equation must be dimensionally homogeneous.

🧠 Memory hook: Dimensions are like paint colours – you can only mix (add) paints of the same colour; mixing different colours gives a meaningless hue.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • Base dimensions are mass (M), length (L) and time (T).
  • Dimensional formula of a derived quantity is obtained by writing it in terms of the base quantities.
  • Principle of homogeneity: all terms on the two sides of a valid equation must have the same dimensions.
  • Only quantities having the same dimensions can be added or subtracted; multiplication/division combines dimensions algebraically.
  • A dimensionless quantity (e.g., solid angle) has the dimensional formula 1 (no M, L or T).

How to approach it

  1. 11. Write the dimensional formula of each quantity using M, L, T.
  2. 22. Apply the homogeneity rule: check that every term added or subtracted on one side has the same dimensions; for products equate the combined dimensions.
  3. 33. If the equation is not homogeneous, it is incorrect or needs modification.
  4. 44. For unknown exponents, equate the powers of M, L and T on both sides and solve.

Worked example — watch it click

Assertion A: Force cannot be added with work. Reason R: Because they both have different dimensions.

  • ✅If both assertion and reason are true and reason is the correct explanation of assertion.
  • B)If both assertion and reason are true but reason is not the correct explanation of assertion.
  • C)If assertion is true but reason is false.
  • D)If both assertion and reason are false.

The concept behind this problem

The worked example forces you to apply the rule that addition is allowed only between like‑dimensional quantities, showing that force and work cannot be added because their dimensional formulas differ.

Step by step

  1. 1Assertion A is true: Force [MLT⁻²] and Work [ML²T⁻²] cannot be added because only quantities with same dimensions can be added.
  2. 2Reason R is true: Force has dimension [MLT⁻²] while Work has dimension [ML²T⁻²] - they are different.
  3. 3Reason R correctly explains why they cannot be added - the fundamental principle is that only quantities with identical dimensions can be added or subtracted.
  4. 4Both true and R explains A.

Watch out

Students often think force and work can be added because both are mechanical quantities, overlooking the dimensional mismatch.

Common slip-ups that cost marks

  • •Confusing units with dimensions – e.g., newton (N) and joule (J) have different dimensions despite both being expressed in SI units.
  • •Treating a dimensionless quantity like solid angle as having a hidden dimension – it is actually 1.
  • •Adding quantities of different dimensions in a multi‑term expression because they appear in the same physical context.

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Practise it

These are real questions from past NEET papers that test this exact idea.

Question 1 of 15NEET 2024

The quantities which have the same dimensions as those of solid angle are:

Push further

More challenging

20 harder questions built from the past papers above — a step up in difficulty, with distractors designed so you can't get there by elimination. Written and checked by our reviewers, not from a real paper.

Question 1 of 20

If 'R' is the gas constant and 'F' is Faraday's constant, what are the dimensions of R/F?