MixedJEE Physics · Original learning card15 original chapter questions

Poiseuille Flow and Hydraulic Resistance

Hagen-Poiseuille flow is steady, fully developed, incompressible Newtonian laminar flow through a long straight circular tube driven by a pressure difference.

Why this shows up in the exam

Flow through capillaries and needles · Comparing pipes in series or parallel · Viscosity measurement from pressure-driven flow

Learn the idea

Laminar flow through a long circular tube is extremely sensitive to radius because resistance varies as the inverse fourth power. No-slip at a tube wall produces a parabolic speed profile. Widening a tube helps every layer and creates much more conducting area, so even a small radius change strongly changes flow.

🧠 Memory hook: For laminar tubes, radius rules to the fourth power.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • Q = pi r⁴ Delta P/(8 eta L) — Poiseuille volume rate under fully developed laminar tube-flow assumptions
  • R_h = 8 eta L/(pi r⁴) — hydraulic resistance defined by Delta P = R_h Q
  • R_series = sum(R_i) — series resistance for the same steady volume rate through consecutive tube segments

How to approach it

  1. 1Verify laminar circular-tube conditions
  2. 2Replace each segment by a hydraulic resistance
  3. 3Use common flow in series and common pressure drop in parallel

Common slip-ups that cost marks

  • •Using diameter to the fourth power without converting constants
  • •Applying Poiseuille's law to turbulent or entrance-region flow
  • •Adding flow rates in series instead of pressure drops

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 15

A wire 1 m long and cross-sectional area 2 mm^2 extends by 1 mm under a 200 N load. Find Young modulus.

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