MixedJEE Physics · Original learning card15 original chapter questions

Stress, Strain, and Hooke's Law

Normal stress is force per perpendicular area and longitudinal strain is fractional length change; in the proportional elastic region they satisfy sigma = Y epsilon.

Why this shows up in the exam

Sizing loaded rods and columns · Reading elastic stress-strain data · Estimating strain under a known axial load

Learn the idea

Within the linear elastic range, stress is proportional to the corresponding strain. A load tells how hard the material is pushed or pulled, while strain tells the fractional deformation; their ratio characterizes the material only while the response remains elastic and linear.

🧠 Memory hook: Stress is load per area; strain is change per original size.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • sigma = F_perpendicular/A — normal tensile or compressive stress for a uniformly loaded section
  • epsilon = Delta L/L — dimensionless longitudinal strain measured from the natural length
  • sigma = Y epsilon — Hooke's law for small longitudinal deformation below the proportional limit

How to approach it

  1. 1Isolate the loaded section and find its internal force
  2. 2Use the area normal to that force
  3. 3Form stress or strain first, then apply the elastic relation

Common slip-ups that cost marks

  • •Using total force instead of the tension in the selected section
  • •Giving strain physical units
  • •Applying the linear law beyond the elastic range

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 15

A wire 1 m long and cross-sectional area 2 mm^2 extends by 1 mm under a 200 N load. Find Young modulus.

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