MixedJEE Physics · Original learning card15 original chapter questions

Elastic Limit, Breaking Stress, and Safety

Breaking stress is the maximum tensile stress sustained before fracture, while an elastic limit bounds recoverable behavior; safe design requires the working stress not to exceed the applicable limit.

Why this shows up in the exam

Crane-rope sizing · Minimum rod diameter · Checking stacked wire loads

Learn the idea

Allowable load is an allowable stress multiplied by the resisting cross-sectional area. A stronger or thicker member can carry more force, but material failure thresholds are stated as stress so geometry must be applied explicitly.

🧠 Memory hook: Limit stress times area gives limit force.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • F_max = sigma_limit A — largest load at a specified stress limit
  • A_min = F_required/sigma_allowable — minimum resisting area
  • factor of safety = sigma_failure/sigma_working — safety ratio when specified

How to approach it

  1. 1Choose elastic, yield, or breaking limit as stated
  2. 2Find the maximum section tension
  3. 3Solve sigma = F/A and apply any safety factor

Common slip-ups that cost marks

  • •Confusing breaking stress with breaking force
  • •Ignoring the heaviest-loaded upper segment
  • •Using radius where area is required

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 15

A wire 1 m long and cross-sectional area 2 mm^2 extends by 1 mm under a 200 N load. Find Young modulus.

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