MixedJEE Physics · Original learning card15 original chapter questions

Steady-State Junctions and Thermal Networks

In a steady thermal network without internal energy storage at a node, energy conservation requires the algebraic sum of branch heat currents H_i=(T_node-T_i)/R_i to be zero.

Why this shows up in the exam

Y-shaped rod junctions · Multi-node composite slabs · Finding interface temperatures from branch conductances

Learn the idea

At a steady junction with no storage, incoming heat currents exactly equal outgoing currents. A junction temperature adjusts until it neither warms nor cools; write every connected branch current with a consistent sign and balance them at that node.

🧠 Memory hook: No heat piles up at a steady junction.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • sum_i (T_node-T_i)/R_i = 0 — steady nodal heat balance
  • H_branch = (T_a-T_b)/R_branch — signed branch heat current between thermal nodes

How to approach it

  1. 1Label every fixed and unknown node temperature
  2. 2Write branch resistances and signed currents
  3. 3Apply zero net current at each unknown node

Common slip-ups that cost marks

  • •Averaging junction temperatures without conductance weights
  • •Changing heat-current sign between branches
  • •Assuming equal currents in a branched network

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 15

A wire 1 m long and cross-sectional area 2 mm^2 extends by 1 mm under a 200 N load. Find Young modulus.

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