MixedJEE Physics · Original learning card5 original chapter questions

Work by a Constant Force

For a constant force, work is the scalar product of force and displacement, so its sign is set by the angle between those vectors and not by force magnitude alone.

Why this shows up in the exam

Forces on straight paths · Work by gravity or normal reaction · Comparing angled pulls

Learn the idea

Work selects the component of force along displacement. A force transfers energy only through the part that points along the actual displacement; a perpendicular push changes direction but does no work.

🧠 Memory hook: Dot force with displacement, not with velocity unless finding power.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • W = F . s = Fs cos(theta) — constant force over displacement s
  • W_net = sum W_i — work contributions add as scalars

How to approach it

  1. 1Draw force and displacement vectors
  2. 2Take their dot product with signs
  3. 3Check the result has units of joules

Common slip-ups that cost marks

  • •Using Fs without cos(theta)
  • •Treating work as a vector
  • •Assigning zero work whenever a force exists

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

Take a timed JEE Physics sectional mock