MixedJEE Physics · Original learning card5 original chapter questions

Variable Force and Work Integrals

Work by a position-dependent force along a specified path is the line integral of F dot dr; in one dimension it is the signed integral of F(x) with respect to x.

Why this shows up in the exam

F-x graph areas · Forces given as functions of position · Piecewise or curved paths

Learn the idea

Variable-force work is accumulated force-displacement area. When force changes from point to point, split the path into tiny steps and add each local dot product; on an F-x graph this becomes signed area.

🧠 Memory hook: Add signed strips under the force-displacement relation.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • W = integral_C F . dr — work along path C
  • W = integral_x1ˣ2 F(x) dx — one-dimensional variable force
  • dW = F . dr — infinitesimal work

How to approach it

  1. 1Parameterize the given path
  2. 2Form F dot dr
  3. 3Integrate with correct limits and sign

Common slip-ups that cost marks

  • •Using endpoint force times distance
  • •Ignoring the stated path
  • •Counting area below the axis as positive

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

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