MixedJEE Physics · Original learning card5 original chapter questions

Potential Energy, Force, and Equilibrium

For one-dimensional conservative motion, F_x is minus dU/dx; equilibrium occurs where dU/dx is zero, with stability determined by local curvature or nearby restoring direction.

Why this shows up in the exam

Reading U-x graphs · Locating turning points and equilibria · Deriving force from potential

Learn the idea

Force points down the potential-energy landscape. A potential graph behaves like a landscape: slope gives the opposite force, valleys are stable, and hills are unstable.

🧠 Memory hook: Force rolls downhill on U(x).

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • F_x = -dU/dx — force from a one-dimensional potential
  • dU/dx = 0 — equilibrium condition
  • d²U/dx² > 0 — stable equilibrium test

How to approach it

  1. 1Differentiate or read the slope
  2. 2Reverse its sign for force
  3. 3Inspect curvature and allowed energy region

Common slip-ups that cost marks

  • •Using U itself as force
  • •Forgetting the minus sign
  • •Calling every zero-slope point stable

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

Take a timed JEE Physics sectional mock