MixedJEE Physics · Original learning card5 original chapter questions

Kinetic Energy and Momentum Relations

For a nonrelativistic particle, K=p^2/(2m) and p=sqrt(2mK), so ratio questions must retain the relevant mass as well as momentum or speed.

Why this shows up in the exam

Mass-momentum-energy ratios · Recoil energy comparisons · Percentage changes in speed or momentum

Learn the idea

Kinetic energy depends on momentum squared divided by mass. Bodies with equal momentum need not have equal kinetic energy; the lighter one carries more kinetic energy for the same momentum.

🧠 Memory hook: At fixed p, lighter means larger K.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • K = p²/(2m) — kinetic energy in terms of momentum
  • p = sqrt(2mK) — momentum in terms of kinetic energy
  • K = (1/2)mv² — kinetic energy in terms of speed

How to approach it

  1. 1Write K=p²/(2m)
  2. 2Form the requested ratio symbolically
  3. 3Substitute numbers only after cancellation

Common slip-ups that cost marks

  • •Assuming K is proportional to p
  • •Ignoring mass in ratio questions
  • •Applying nonrelativistic formulas at relativistic speeds

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

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