MixedJEE Physics · Original learning card5 original chapter questions

Coefficient of Restitution and Rebounds

The coefficient of restitution is the relative speed of separation divided by the relative speed of approach along the line of impact, with 0<=e<=1 for ordinary passive impacts.

Why this shows up in the exam

Ball-floor rebounds · Repeated wall impacts · Oblique impacts with smooth surfaces

Learn the idea

Restitution compares separation speed with approach speed along impact. A bounce remembers the normal relative-speed ratio through e; tangential motion needs a separate smoothness or friction condition.

🧠 Memory hook: Approach becomes separation, scaled by e.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • e = (v₂-v₁)/(u₁-u₂) — one-dimensional signed restitution
  • h_rebound = e² h_drop — vertical bounce under uniform gravity
  • v_n,after = -e v_n,before — impact with a fixed smooth surface

How to approach it

  1. 1Mark the line of impact
  2. 2Write signed approach and separation velocities
  3. 3Combine restitution with momentum or flight energy

Common slip-ups that cost marks

  • •Using speed magnitudes without direction
  • •Applying e to tangential velocity
  • •Assuming e equals retained energy fraction

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

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