MixedJEE Physics · Original learning card5 original chapter questions

One-Dimensional Elastic Collisions

A perfectly elastic head-on collision is determined by conservation of linear momentum together with relative speed of separation equal to relative speed of approach.

Why this shows up in the exam

Head-on mass collisions · Maximum energy transfer · Collision chains

Learn the idea

A one-dimensional elastic collision conserves momentum and kinetic energy. For equal masses, velocities exchange; for unequal masses, mass contrast controls reversal, transfer, and energy sharing.

🧠 Memory hook: Momentum plus relative speed solves elastic head-on impacts.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • m1u1+m2u2 = m1v1+m2v2 — momentum conservation
  • u1-u2 = -(v1-v2) — elastic relative-speed rule
  • v1 = ((m1-m2)u1+2m2u2)/(m1+m2) — first-body final velocity

How to approach it

  1. 1Choose one positive direction
  2. 2Write momentum conservation
  3. 3Apply e=1 and test limiting cases

Common slip-ups that cost marks

  • •Conserving each body kinetic energy
  • •Using equal-mass exchange for unequal masses
  • •Losing signs when a body rebounds

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

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