MixedJEE Physics · Original learning card5 original chapter questions

Inelastic Collisions and Energy Loss

In a perfectly inelastic collision the bodies coalesce and momentum is conserved when external impulse is negligible, while kinetic-energy loss is the positive difference K_i-K_f.

Why this shows up in the exam

Bullets embedding in blocks · Bodies that coalesce · Successive sticking collisions

Learn the idea

Momentum may be conserved while kinetic energy decreases. Sticking bodies share a final velocity, and missing kinetic energy becomes deformation, heat, sound, or internal energy.

🧠 Memory hook: Stick first with momentum; count energy loss afterward.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • m1u1+m2u2 = (m1+m2)V — one-dimensional sticking collision
  • Delta K_loss = K_i-K_f — kinetic energy converted internally
  • K_loss = (1/2)mu(u1-u2)² — two-body perfectly inelastic loss

How to approach it

  1. 1Conserve vector momentum through impact
  2. 2Find the shared final velocity
  3. 3Compute kinetic-energy loss separately

Common slip-ups that cost marks

  • •Conserving kinetic energy while bodies stick
  • •Applying energy conservation across deformation
  • •Using center-of-mass speed for one body

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A 2 kg body speeds up from 3 m/s to 7 m/s. What net work is done on it?

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