Fundamentals

1,200 must-knows for NEET & JEE

The core facts every aspirant should own — each a titled nugget with a real-world story, the concept in plain words, and a memory trick. Works even when the internet doesn't.

1,200 fundamentals

ChemistryStructure of Atom· Class 11

E_n = −13.6 Z²/n² eV

“When you see the red hydrogen line in a nebula, its wavelength comes from electrons dropping between levels given by E_n = -13.6 Z²/n² eV.”

For any hydrogen-like ion (one electron, nuclear charge Z) the bound-state energy is E_n = –13.6 Z²/n² eV. The negative sign indicates a bound electron; the magnitude grows with Z and shrinks with n². Photon energy emitted = |ΔE| = |E_final – E_initial|, never the signed ΔE. Forgetting the sign or using Z of a neutral atom is a common mistake.

E_n = −13.6 Z²/n² eV

Memory trick: E_n = –13.6·Z²÷n²: negative, 13.6 for H, square Z, divide n²

ChemistryStructure of Atom· Class 11

orbit vs orbital

“Bohr’s planet-like orbit is like a marble on a track, while an orbital is a fuzzy cloud where the marble could be anywhere.”

An orbit is the fixed circular path from Bohr’s outdated model; an orbital is the three-dimensional region of high probability from quantum mechanics. Modern chemistry and physics use only orbitals. Trap: never use ‘orbit’ for electron placement in JEE/NEET problems.

Memory trick: Orbit = track; Orbital = cloud

ChemistryStructure of Atom· Class 11

shell vs subshell

“Think of a building: each floor is a shell (n=1,2,3…) and each room on a floor is a subshell (s, p, d, f, …).”

A shell is defined by the principal quantum number n, setting the main energy level. A subshell is set by the azimuthal quantum number ℓ, which can be any integer from 0 to n-1; letters s, p, d, f correspond to ℓ=0,1,2,3, but for n≥5 higher-ℓ subshells (g, h…) exist. The common mistake is to think ℓ never exceeds 3.

Memory trick: ℓ = 0…n-1; s=0, p=1, d=2, f=3, g=4…

ChemistryStructure of Atom· Class 11

Aufbau principle vs Hund's rule

“Electrons fill orbitals like cars taking the nearest empty parking spot: the spot with the smallest (n+ℓ) gets occupied first.”

Aufbau orders orbital filling by increasing (n+ℓ); when two subshells share the same (n+ℓ), the one with lower n fills first (e.g., 3d before 4p). Hund’s rule then says electrons in a subshell occupy separate orbitals with parallel spins before pairing. Forgetting the tie-breaker is a frequent exam trap.

Memory trick: Aufbau: low (n+ℓ) first; tie → lower n.

ChemistryStructure of Atom· Class 11

Myth: Cr and Cu configurations

“Chromium’s extra stability is like a soccer team with five defenders (3d⁵) and one goalkeeper (4s¹) – half-filled defense is strongest.”

Cr has the ground state [Ar] 3d⁵ 4s¹ and Cu [Ar] 3d¹⁰ 4s¹ because half-filled (Cr) or fully-filled (Cu) d subshells lower the energy. The usual writing 3d⁴ 4s² or 3d⁹ 4s² is incorrect. Trap: always check for extra stability of d⁵ or d¹⁰ before assigning electrons.

Memory trick: Cr: 3d⁵4s¹ (half), Cu: 3d¹⁰4s¹ (full)

ChemistryChemical Bonding & Molecular Structure· Class 11

Octet rule

“When sodium metal reacts with chlorine, Na gives up one electron to become Na⁺, achieving a neon-like octet.”

Atoms aim for a full valence shell of eight electrons (the octet). They lose, gain or share electrons to reach the nearest noble-gas configuration. In JEE/NEET, remember period-2 elements cannot have expanded octets and electron-deficient molecules (e.g., BF₃) break the rule.

Memory trick: Lose-Gain-Share → reach 8

ChemistryChemical Bonding & Molecular Structure· Class 11

Octet rule — common mistake

“BeCl₂ is like a two-handed glove; it’s stable with only four valence electrons, not a full octet.”

Elements such as Be, B, Al form electron-deficient compounds with less than eight electrons around the central atom. Sulphur in SF₆ can use d-orbitals to hold more than eight electrons, giving an expanded octet. The exam trap is to force an octet on every molecule—first check the element’s period and possible d-orbital use.

Memory trick: Be, B, Al → ≤8; S, P, Cl → can expand.

ChemistryChemical Bonding & Molecular Structure· Class 11

VSEPR theory — common mistake

“In a crowded elevator, lone pairs are the bulky passengers that push bonding pairs closer together.”

VSEPR states that all electron pairs (bonding and lone) arrange to maximize separation, determining molecular shape. Lone pairs occupy more space than bonding pairs, so they compress adjacent bond angles. Ignoring lone pairs leads to wrong predictions, e.g., calling H₂O linear instead of bent.

Memory trick: Lone > Bond → smaller angles.

ChemistryChemical Bonding & Molecular Structure· Class 11

Hybridization

“A sp³ hybrid is like mixing red, green, blue, and yellow paints to get a uniform shade for a tetrahedral sculpture.”

Hybridization mixes the central atom’s s and p orbitals to form equivalent hybrid orbitals (sp, sp², sp³) that dictate geometry. The number of hybrids equals the steric number (σ bonds + lone pairs). Exams match sp³ → tetrahedral, sp² → trigonal planar, sp → linear.

Memory trick: Hybrid count = σ + LP; sp³ =4, sp² =3, sp =2.

ChemistryChemical Bonding & Molecular Structure· Class 11

Hybridization — common mistake

“Counting only bonds for NH₃ is like counting chairs without noting the empty seat; the lone pair forces sp³ hybridization.”

When assigning hybridization, include both σ bonds and lone pairs in the steric number. Ignoring lone pairs gives wrong hybrids, e.g., NH₃ is sp³ (3 bonds + 1 lone pair) not sp². The common pitfall is equating hybrid type with number of bonds alone.

Memory trick: Hybrid = bonds + lone pairs.

ChemistryChemical Bonding & Molecular Structure· Class 11

Molecular polarity

“CO₂ is like two equally strong magnets placed back-to-back; their forces cancel, making the molecule non-polar.”

A molecule is polar only if the vector sum of its bond dipoles is non-zero. Both electronegativity differences and geometry matter; symmetric shapes (CO₂, BF₃) cancel dipoles despite polar bonds. The trap is to label any molecule with polar bonds as polar without checking symmetry.

Memory trick: Polar bonds + asymmetry = polar molecule.

ChemistryChemical Bonding & Molecular Structure· Class 11

Molecular polarity — common mistake

“Like a seesaw, if the heavy side (strong bond dipole) isn’t balanced by the shape, the molecule tips and stays polar.”

A molecule is polar only when the vector sum of its bond dipoles is non-zero. Both electronegativity difference and molecular geometry decide this. The common trap is to label any molecule with polar bonds as polar, ignoring symmetry.

Memory trick: Polar = Polar bonds + Asymmetry (P + A)

ChemistryChemical Bonding & Molecular Structure· Class 11

Hydrogen bonding — common mistake

“Water’s surface tension lets a paperclip float—thanks to hydrogen bonds between H of one molecule and O of another.”

Hydrogen bonding is a strong dipole-dipole attraction when H is covalently bonded to N, O or F and interacts with a lone pair on another electronegative atom. It is not a covalent bond. Exam trap: counting H-bonds as covalent or overlooking them in boiling-point questions.

Memory trick: H-bond: H-(N/O/F) → strong dipole

ChemistryChemical Bonding & Molecular Structure· Class 11

ionic bond vs covalent bond

“A sodium atom passes its outer electron to chlorine like a basketball player handing off the ball, creating Na⁺ and Cl⁻ that snap together.”

Ionic bonds form when a metal loses electrons and a non-metal gains them, producing opposite ions that attract electrostatically. Covalent bonds involve non-metals sharing electron pairs; the bond is non-polar if ΔEN≈0 and polar if ΔEN is moderate. Exam trap: ΔEN > 1.7 usually means ionic, but small highly-charged ions (e.g., Be²⁺) can give covalent character despite a large ΔEN.

Memory trick: Ionic = I (transfer), Covalent = C (common/share).

ChemistryChemical Bonding & Molecular Structure· Class 11

sigma bond vs pi bond

“A sigma bond is like a handshake (front-to-front), while a pi bond is a side-by-side high-five of p-orbitals.”

Sigma (σ) bonds arise from head-on overlap of orbitals; they are present in all single bonds and are the strongest. Pi (π) bonds come from sideways overlap of parallel p-orbitals, appear in double/triple bonds and are weaker, restricting rotation. Trap: forgetting that rotation is free only about σ, not about π.

Memory trick: σ = head-on, π = side-on

ChemistryChemical Bonding & Molecular Structure· Class 11

polar molecule vs non-polar molecule

“A water droplet clings to a leaf because its bent shape makes the O–H dipoles add up, giving a net dipole.”

A polar molecule has a non-zero dipole moment; the vector sum of all bond dipoles does not cancel. This occurs when bonds are unequal or the molecular geometry is asymmetric (e.g., H₂O, NH₃). Linear molecules can be polar if the ends differ (CO, HCN). The trap is to label every linear molecule non-polar and every bent one polar without checking symmetry.

Memory trick: Resultant dipole ≠0 → polar; symmetry → cancel.

ChemistryChemical Bonding & Molecular Structure· Class 11

Myth: Calling CO₂ polar

“Even though each C=O bond pulls electrons, the straight line of CO₂ makes the pulls opposite, so the molecule is neutral.”

CO₂’s C=O bonds are polar, but the molecule is linear (180°), so the bond dipoles are equal and opposite, giving zero overall dipole. The myth arises from focusing only on bond polarity. In exams, choose non-polar for CO₂.

Memory trick: CO₂: 180° → dipoles cancel

ChemistryChemical Thermodynamics· Class 11

Enthalpy (H)

“When you light a match, the flame releases heat – the reaction’s ΔH is negative.”

ΔH is the heat exchanged at constant pressure for the reacting system. Exothermic reactions give ΔH < 0 (heat leaves), endothermic give ΔH > 0 (heat absorbed). Trap: mixing up system sign with surrounding heat flow.

Memory trick: Heat out = ΔH<0; Heat in = ΔH>0

ChemistryChemical Thermodynamics· Class 11

Enthalpy (H) — common mistake

“When an ice-pack gets cold, the dissolving salts absorb heat – the reaction’s ΔH is positive, not negative.”

The sign of ΔH follows the system’s heat flow: heat released → ΔH negative, heat absorbed → ΔH positive. A common error is writing the opposite sign because the surroundings feel hot or cold. Remember the sign belongs to the system.

Memory trick: System loses heat → ΔH<0; gains heat → ΔH>0

ChemistryChemical Thermodynamics· Class 11

Entropy (S)

“A shuffled deck of cards has many possible orders – that’s high entropy.”

Entropy quantifies the number of microscopic arrangements (microstates). For a spontaneous change, the total entropy change (system + surroundings) must be positive. Trap: assuming ΔS_sys alone must increase.

Memory trick: ΔS_total = ΔS_sys + ΔS_surr >0 for spontaneity

ChemistryChemical Thermodynamics· Class 11

Entropy (S) — common mistake

“Ice melting looks ordered, but the surrounding air gains disorder – total entropy rises.”

Students often think only the system’s entropy must rise. In reality the universe’s entropy (system + surroundings) must increase; the surroundings can compensate a decrease in the system. Ignoring ΔS_surr leads to wrong conclusions.

Memory trick: ΔS_universe = ΔS_sys + ΔS_surr must be >0

ChemistryChemical Thermodynamics· Class 11

Gibbs free energy — common mistake

“A cold endothermic reaction can still run spontaneously in a warm kitchen because TΔS outweighs ΔH.”

ΔG = ΔH – TΔS, not just ΔH, governs spontaneity. Even an endothermic reaction (ΔH > 0) can be spontaneous if TΔS is large and positive, making ΔG negative. Trap: overlooking the TΔS contribution or sign of ΔS.

Memory trick: ΔG<0 → spontaneous; check both ΔH and TΔS

ChemistryChemical Thermodynamics· Class 11

Hess's law — common mistake

“Baking a cake in one big bowl or in several small bowls uses the same total heat.”

Hess’s law states that the enthalpy change of a reaction equals the sum of enthalpy changes of any series of steps that connect reactants to products. Enthalpy is a state function, so the path taken does not matter. A common trap is forgetting that reversing a step changes the sign of ΔH.

Memory trick: ΔH_total = ΣΔH_steps; reverse step → opposite sign.

ChemistryChemical Thermodynamics· Class 11

ΔG = ΔH − TΔS

“A ball on a hill (ΔH) rolls down spontaneously only if the wind (TΔS) pushes it enough.”

ΔG = ΔH – TΔS predicts spontaneity at constant temperature and pressure. If ΔG is negative the process is spontaneous, zero at equilibrium, positive non-spontaneous. Trap: applying the equation when T changes during the reaction or mixing up the sign of ΔS.

ΔG = ΔH − TΔS

Memory trick: G = H – TS; negative G → go!

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