Electrochemistry

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ChemistryElectrochemistry

Calculate emf of the half cell given below: Pt(s)|H₂(g, 2 atm)|HCl(aq, 0.02 M) E°H₂/H⁺ = 0 V (Given: 2.303 RT/F = 0.059 log 2 = 0.3010)

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