Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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PhysicsClass 112 marksmedium

Gravitation

Write the expression for the gravitational potential energy of a mass m at a distance r from the centre of the Earth (mass M), and explain why it is negative.

Reveal model answer + marking points▾

U = - G M m / r. It is negative because the gravitational force is attractive: zero potential energy is taken at infinity, and as the mass is brought closer, work is done by gravity, lowering the energy below zero. The negative sign shows the mass is in a bound state.

U = - G M m / r

Marking-scheme points

  • ✓U = - G M m / r
  • ✓Reference: U = 0 at infinity
  • ✓Negative => attractive, bound system
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PhysicsClass 113 marksmedium

Units and Measurements

State any two uses and two limitations of dimensional analysis.

Reveal model answer + marking points▾

Uses: (i) to check the dimensional consistency of an equation; (ii) to convert a quantity from one system of units to another; (iii) to derive the relation between physical quantities. Limitations: (i) it cannot find dimensionless constants (like 1/2 or 2 pi); (ii) it cannot be used if a quantity depends on more than three others, or on trigonometric/exponential/logarithmic functions.

Marking-scheme points

  • ✓Uses: check equations, convert units, derive relations
  • ✓Limits: cannot give numerical constants
  • ✓Fails for trig/exp/log functions
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PhysicsClass 113 markshard

Laws of Motion

Why are roads banked at curves? Write the expression for the ideal speed on a frictionless banked road of angle theta and radius r.

Reveal model answer + marking points▾

Roads are banked at curves so that the horizontal component of the normal reaction provides the centripetal force needed to turn, reducing reliance on friction and the risk of skidding. On a frictionless banked road, the ideal (safe) speed is v = sqrt(r g tan(theta)).

v = sqrt(r g tan(theta))

Marking-scheme points

  • ✓Banking supplies centripetal force via normal reaction
  • ✓Reduces dependence on friction
  • ✓v = sqrt(r g tan theta)
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