Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

269 questions · clear filters

PhysicsClass 122 markseasy

Electric Charges and Fields

State Coulomb's law of electrostatics and write its mathematical form.

Reveal model answer + marking points▾

Coulomb's law states that the force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them, acting along the line joining them. Mathematically, F = k q1 q2 / r^2, where k = 1/(4 pi epsilon0) = 9 x 10^9 N m^2 C^-2 in free space.

F = k q1 q2 / r^2

Marking-scheme points

  • ✓F is proportional to product of charges and to 1/r^2
  • ✓F = k q1 q2 / r^2 along the line joining them
  • ✓k = 1/(4 pi epsilon0) = 9 x 10^9 N m^2 C^-2

The concept

Coulomb's law gives the electric force between two charges: it grows with charge and falls with distance squared.

Why it matters

It's the electrostatic backbone of atoms, capacitors and all of electronics.

💡 Memory trick

Like gravity but for charge: F = k q1 q2 / r^2. Same charges repel, opposite attract.

Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Electric Charges and Fields

Define electric field intensity at a point. State its SI unit.

Reveal model answer + marking points▾

The electric field intensity at a point is the force experienced by a unit positive test charge placed at that point. It is a vector quantity given by E = F/q0, where q0 is the small positive test charge. Its SI unit is newton per coulomb (N/C) or equivalently volt per metre (V/m).

E = F/q0

Marking-scheme points

  • ✓E = force per unit positive test charge = F/q0
  • ✓Vector quantity, directed along the force on a positive charge
  • ✓SI unit: N/C or V/m
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Electric Charges and Fields

Derive the expression for the torque acting on an electric dipole placed in a uniform electric field.

Reveal model answer + marking points▾

When a dipole of moment p is placed in a uniform electric field E at an angle theta, the two charges experience equal and opposite forces qE, forming a couple. The magnitude of the torque = force x perpendicular distance = qE x (2a sin theta) = (q x 2a) E sin theta = pE sin theta. In vector form, torque = p x E. The torque tends to align the dipole with the field.

torque = pE sin theta = p x E

Marking-scheme points

  • ✓Equal and opposite forces qE form a couple
  • ✓Torque = pE sin theta (magnitude)
  • ✓Vector form: torque = p x E; aligns dipole with field
Still unsure? Ask the AI tutor →
Page 1 of 14Next →

You are more ready than you feel.

One question at a time is how every topper started. Bookmark this, revise a few each day, and watch the fear shrink. And if a friend is stressing about boards — send this their way. You both win.