Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questionsModel answersMarking-scheme pointsEvery chapterCBSE · ISC · State boards

269 questions · clear filters

PhysicsClass 122 marksmedium

Dual Nature of Radiation and Matter

Define work function and threshold frequency.

Reveal model answer + marking points

The work function (W0) of a metal is the minimum energy required to just remove an electron from the surface of the metal without giving it any kinetic energy. The threshold frequency (f0) is the minimum frequency of the incident light below which no photoelectric emission takes place, however intense the light may be. They are related by W0 = h f0, where h is Planck's constant.

W0 = h f0

Marking-scheme points

  • Work function W0 = minimum energy to free an electron
  • Threshold frequency f0 = minimum frequency for emission
  • Relation: W0 = h f0
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Dual Nature of Radiation and Matter

State any two laws of the photoelectric effect.

Reveal model answer + marking points

(1) For a given metal, photoelectric emission occurs only if the frequency of the incident light is greater than a certain minimum value (threshold frequency), whatever the intensity. (2) The maximum kinetic energy of the emitted photoelectrons depends on the frequency of the incident light and the nature of the metal, but is independent of the intensity of the light. (3) The number of photoelectrons emitted per second (photoelectric current) is directly proportional to the intensity of the incident light. (4) The emission is instantaneous, with no measurable time lag.

Marking-scheme points

  • Emission only above the threshold frequency
  • Max KE depends on frequency, not on intensity
  • Number of photoelectrons is proportional to intensity; emission is instantaneous
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Dual Nature of Radiation and Matter

What is the de Broglie hypothesis? Write the expression for the de Broglie wavelength.

Reveal model answer + marking points

The de Broglie hypothesis states that every moving particle has a wave associated with it, called a matter wave. The de Broglie wavelength is lambda = h/p = h/(m v), where h is Planck's constant, p is the momentum, m is the mass and v the velocity of the particle. In terms of kinetic energy, lambda = h/sqrt(2 m KE). This shows the dual (wave-particle) nature of matter; the wavelength is significant only for very small particles like electrons.

lambda = h/(m v)

Marking-scheme points

  • Every moving particle has an associated matter wave
  • lambda = h/p = h/(m v)
  • In terms of KE: lambda = h/sqrt(2 m KE)
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Atoms

State the main conclusions of Rutherford's alpha-particle scattering experiment.

Reveal model answer + marking points

From the scattering of alpha particles by a thin gold foil, Rutherford concluded that: (1) most of the atom is empty space, since most alpha particles passed straight through; (2) the entire positive charge and almost all the mass of the atom are concentrated in a very small central region called the nucleus, since a few alpha particles were deflected through large angles; and (3) the electrons revolve around the nucleus, and the size of the nucleus is very small compared with the size of the atom.

Marking-scheme points

  • Most of the atom is empty space
  • Positive charge and mass concentrated in a tiny nucleus
  • Electrons revolve around the nucleus
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Atoms

The energy of an electron in the ground state of hydrogen is -13.6 eV. Calculate the energy of the electron in the second orbit (n = 2).

Reveal model answer + marking points

The energy of the electron in the nth orbit of hydrogen is En = -13.6/n^2 eV. For n = 2, E2 = -13.6/2^2 = -13.6/4 = -3.4 eV. The negative sign shows that the electron is bound to the nucleus, and the energy increases (becomes less negative) as n increases.

En = -13.6/n^2 eV

Marking-scheme points

  • En = -13.6/n^2 eV
  • E2 = -13.6/4
  • E2 = -3.4 eV
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Atoms

State two limitations of Bohr's model of the atom.

Reveal model answer + marking points

(1) Bohr's model applies successfully only to hydrogen and hydrogen-like single-electron atoms; it fails to explain the spectra of atoms having more than one electron. (2) It could not explain the fine structure of spectral lines or the relative intensities of the lines, and it does not account for the splitting of spectral lines in electric and magnetic fields (the Stark and Zeeman effects). Also, it arbitrarily assumes quantisation without explaining it (later explained by de Broglie).

Marking-scheme points

  • Works only for hydrogen/single-electron atoms
  • Cannot explain fine structure or relative intensities of lines
  • Cannot explain Zeeman/Stark effects; quantisation assumed arbitrarily
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Nuclei

State Einstein's mass-energy relation. What is the energy equivalent of 1 atomic mass unit (u)?

Reveal model answer + marking points

Einstein's mass-energy relation is E = m c^2, which states that mass and energy are interconvertible, where c is the speed of light. Using this relation, the energy equivalent of 1 atomic mass unit (1 u = 1.66 x 10^-27 kg) is about 931 MeV (mega electron volt). This relation explains the large amount of energy released in nuclear reactions such as fission and fusion.

E = m c^2; 1 u = 931 MeV

Marking-scheme points

  • E = m c^2 (mass and energy are interconvertible)
  • 1 u is equivalent to about 931 MeV
  • Explains energy released in nuclear reactions
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Nuclei

Define mass defect and binding energy of a nucleus.

Reveal model answer + marking points

The mass defect is the difference between the sum of the masses of the individual protons and neutrons (nucleons) and the actual mass of the nucleus; the actual nuclear mass is always less than the sum. This missing mass (delta m) is converted into energy that binds the nucleons together. The binding energy is the energy equivalent of the mass defect, BE = (delta m) c^2; it is the energy required to break the nucleus into its constituent nucleons.

BE = (delta m) c^2

Marking-scheme points

  • Mass defect = (sum of nucleon masses) - (actual nuclear mass)
  • This mass is converted into binding energy
  • Binding energy = (delta m) c^2
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Nuclei

Name the three types of radioactive radiations and state their nature.

Reveal model answer + marking points

The three types of radioactive radiations are: (1) alpha rays, which are helium nuclei (2 protons + 2 neutrons), positively charged and with low penetrating power; (2) beta rays, which are fast-moving electrons, negatively charged and with greater penetrating power than alpha rays; and (3) gamma rays, which are high-energy electromagnetic waves (photons), electrically neutral and with very high penetrating power. In a magnetic field, alpha and beta rays are deflected in opposite directions while gamma rays are undeflected.

Marking-scheme points

  • Alpha: helium nuclei, positive, low penetration
  • Beta: fast electrons, negative, moderate penetration
  • Gamma: high-energy EM waves, neutral, high penetration
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Nuclei

What is nuclear fission? Give one example.

Reveal model answer + marking points

Nuclear fission is the process in which a heavy nucleus (such as uranium-235) splits into two lighter nuclei of comparable masses, with the release of a few neutrons and a large amount of energy. For example, when a uranium-235 nucleus captures a slow neutron, it splits into barium and krypton nuclei plus three neutrons and energy. The released neutrons can cause further fissions, leading to a chain reaction, which is used in nuclear reactors and atom bombs.

Marking-scheme points

  • Heavy nucleus splits into two lighter nuclei with energy release
  • Example: U-235 + neutron -> lighter nuclei + neutrons + energy
  • Released neutrons can cause a chain reaction
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Nuclei

What is nuclear fusion? Why does it require very high temperature?

Reveal model answer + marking points

Nuclear fusion is the process in which two light nuclei (such as isotopes of hydrogen) combine to form a heavier nucleus, with the release of an enormous amount of energy. It is the source of energy of the sun and stars, where hydrogen nuclei fuse to form helium. It requires very high temperature (millions of degrees) because the positively charged nuclei must overcome their strong electrostatic repulsion to come close enough to fuse.

Marking-scheme points

  • Two light nuclei combine into a heavier nucleus with energy release
  • Source of energy of the sun and stars (hydrogen to helium)
  • Needs very high temperature to overcome electrostatic repulsion
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Semiconductor Electronics

Distinguish between intrinsic and extrinsic semiconductors.

Reveal model answer + marking points

An intrinsic semiconductor is a pure semiconductor (such as pure silicon or germanium) with no added impurity; its conductivity is low and is due to the equal number of electrons and holes generated thermally. An extrinsic semiconductor is one to which a small amount of a suitable impurity has been added (doping); this greatly increases its conductivity. Extrinsic semiconductors are of two types, n-type and p-type.

Marking-scheme points

  • Intrinsic: pure semiconductor, low conductivity, equal electrons and holes
  • Extrinsic: doped with impurity, higher conductivity
  • Extrinsic types: n-type and p-type
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Semiconductor Electronics

How are n-type and p-type semiconductors formed? Name the majority charge carriers in each.

Reveal model answer + marking points

An n-type semiconductor is formed by doping a pure semiconductor (silicon) with a pentavalent impurity (such as phosphorus or arsenic), which donates free electrons; the majority carriers are electrons and the minority carriers are holes. A p-type semiconductor is formed by doping with a trivalent impurity (such as boron or aluminium), which creates holes; the majority carriers are holes and the minority carriers are electrons. Both types are electrically neutral overall.

Marking-scheme points

  • n-type: pentavalent doping (phosphorus); majority carriers = electrons
  • p-type: trivalent doping (boron); majority carriers = holes
  • Both are electrically neutral overall
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Semiconductor Electronics

What is a depletion region and potential barrier in a p-n junction?

Reveal model answer + marking points

When a p-n junction is formed, electrons from the n-side diffuse into the p-side and holes from the p-side diffuse into the n-side, and they recombine near the junction. This leaves a region near the junction that has no free charge carriers but has immobile charged ions; this region is called the depletion region (or depletion layer). The immobile ions set up an internal electric field that opposes further diffusion; the potential difference developed across the depletion region is called the potential barrier.

Marking-scheme points

  • Depletion region: layer near the junction with no free carriers
  • Formed by diffusion and recombination of electrons and holes
  • Potential barrier: potential difference across the depletion region
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Semiconductor Electronics

Distinguish between forward biasing and reverse biasing of a p-n junction diode.

Reveal model answer + marking points

In forward biasing, the p-side is connected to the positive terminal and the n-side to the negative terminal of the battery; this reduces the width of the depletion region and the potential barrier, so a large current flows and the diode conducts. In reverse biasing, the p-side is connected to the negative terminal and the n-side to the positive terminal; this increases the width of the depletion region and the potential barrier, so only a very small (negligible) current flows and the diode does not conduct.

Marking-scheme points

  • Forward bias: p to +, n to -; barrier reduced, diode conducts
  • Reverse bias: p to -, n to +; barrier increased, negligible current
  • Diode acts as a one-way valve for current
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Semiconductor Electronics

What is a Zener diode? State its main use.

Reveal model answer + marking points

A Zener diode is a special heavily doped p-n junction diode designed to operate in the reverse breakdown region without being damaged. In this region, the voltage across it remains almost constant (equal to its Zener voltage) even when the current through it changes over a wide range. Because of this property, its main use is as a voltage regulator, that is, to provide a constant output voltage to a load in spite of changes in the input voltage or load current.

Marking-scheme points

  • Heavily doped diode that works in reverse breakdown safely
  • Voltage across it stays constant (Zener voltage)
  • Main use: voltage regulator
Still unsure? Ask the AI tutor →
ChemistryClass 122 markseasy

The Solid State

Distinguish between crystalline and amorphous solids with one example each.

Reveal model answer + marking points

Crystalline solids have a regular, long-range ordered arrangement of particles, sharp melting points, definite geometrical shapes and are anisotropic (properties differ with direction); e.g. sodium chloride and diamond. Amorphous solids have only a short-range order (irregular arrangement), no sharp melting point (they soften over a range), no definite shape and are isotropic (same properties in all directions); e.g. glass and rubber.

Marking-scheme points

  • Crystalline: long-range order, sharp melting point, anisotropic (NaCl)
  • Amorphous: short-range order, no sharp melting point, isotropic (glass)
  • Amorphous solids soften over a range of temperature
Still unsure? Ask the AI tutor →
ChemistryClass 122 markseasy

The Solid State

What is a unit cell? Distinguish between a primitive and a centred unit cell.

Reveal model answer + marking points

A unit cell is the smallest repeating three-dimensional portion of a crystal lattice which, when repeated in different directions, generates the entire crystal. In a primitive (simple) unit cell, the constituent particles are present only at the corners of the unit cell. In a centred unit cell, particles are present at positions other than the corners as well, such as body-centred (one at the centre of the body), face-centred (one at the centre of each face) or end-centred.

Marking-scheme points

  • Unit cell = smallest repeating unit of a crystal lattice
  • Primitive: particles only at the corners
  • Centred: extra particles (body-, face- or end-centred)
Still unsure? Ask the AI tutor →
ChemistryClass 122 marksmedium

The Solid State

Distinguish between Schottky and Frenkel defects.

Reveal model answer + marking points

Schottky defect is a vacancy defect in which an equal number of cations and anions are missing from their lattice sites, so the density of the solid decreases; it occurs in ionic solids with high coordination number and similar cation and anion sizes (e.g. NaCl, KCl). Frenkel defect is a dislocation defect in which an ion (usually the smaller cation) leaves its lattice site and occupies an interstitial site, so the density remains unchanged; it occurs in solids with a large difference in the sizes of the ions (e.g. AgCl, ZnS).

Marking-scheme points

  • Schottky: equal cations and anions missing; density decreases (NaCl)
  • Frenkel: smaller ion shifts to an interstitial site; density unchanged (AgCl)
  • Both are point defects in ionic solids
Still unsure? Ask the AI tutor →
ChemistryClass 122 marksmedium

The Solid State

State the packing efficiency and coordination number of simple cubic, bcc and fcc structures.

Reveal model answer + marking points

Packing efficiency is the percentage of the total space occupied by the particles. Simple cubic: packing efficiency 52.4 percent, coordination number 6. Body-centred cubic (bcc): packing efficiency 68 percent, coordination number 8. Face-centred cubic (fcc, also ccp/hcp): packing efficiency 74 percent (the highest), coordination number 12.

Marking-scheme points

  • Simple cubic: 52.4 percent, coordination number 6
  • bcc: 68 percent, coordination number 8
  • fcc/ccp/hcp: 74 percent (highest), coordination number 12
Still unsure? Ask the AI tutor →
← PrevPage 3 of 14Next →

You are more ready than you feel.

One question at a time is how every topper started. Bookmark this, revise a few each day, and watch the fear shrink. And if a friend is stressing about boards — send this their way. You both win.