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The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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MathsClass 122 markseasy

Relations and Functions

Define reflexive, symmetric and transitive relations. When is a relation called an equivalence relation?

Reveal model answer + marking points▾

A relation R on a set A is reflexive if (a, a) belongs to R for every a in A. It is symmetric if (a, b) in R implies (b, a) in R. It is transitive if (a, b) in R and (b, c) in R together imply (a, c) in R. A relation that is reflexive, symmetric and transitive at the same time is called an equivalence relation.

Marking-scheme points

  • ✓Reflexive: (a, a) in R for all a
  • ✓Symmetric: (a, b) in R => (b, a) in R
  • ✓Transitive: (a, b), (b, c) in R => (a, c) in R; all three => equivalence
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MathsClass 123 marksmedium

Relations and Functions

Show that the relation R on the set of integers Z defined by aRb if (a - b) is divisible by 3 is an equivalence relation.

Reveal model answer + marking points▾

Reflexive: for any integer a, a - a = 0, which is divisible by 3, so (a, a) in R. Symmetric: if (a - b) is divisible by 3, then (b - a) = -(a - b) is also divisible by 3, so aRb implies bRa. Transitive: if (a - b) and (b - c) are both divisible by 3, then their sum (a - b) + (b - c) = (a - c) is also divisible by 3, so aRb and bRc imply aRc. Since R is reflexive, symmetric and transitive, it is an equivalence relation.

Marking-scheme points

  • ✓Reflexive: a - a = 0 divisible by 3
  • ✓Symmetric: (a - b) divisible => (b - a) divisible
  • ✓Transitive: sum (a - b) + (b - c) = (a - c) divisible; hence equivalence
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MathsClass 122 markseasy

Relations and Functions

Define one-one (injective), onto (surjective) and bijective functions.

Reveal model answer + marking points▾

A function f from A to B is one-one (injective) if distinct elements of A have distinct images, that is, f(x1) = f(x2) implies x1 = x2. It is onto (surjective) if every element of B has at least one pre-image in A, that is, the range of f equals the codomain B. A function that is both one-one and onto is called bijective (a one-to-one correspondence).

Marking-scheme points

  • ✓One-one: f(x1) = f(x2) => x1 = x2
  • ✓Onto: range = codomain (every element of B has a pre-image)
  • ✓Bijective: both one-one and onto
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