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800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.
ChemistryClass 123 marksmedium
Electrochemistry
State Kohlrausch's law of independent migration of ions and give one application.
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Kohlrausch's law states that at infinite dilution, the molar conductivity of an electrolyte is the sum of the individual contributions of its cations and anions, each migrating independently. Mathematically, the limiting molar conductivity = (number of cations x limiting molar conductivity of cation) + (number of anions x limiting molar conductivity of anion). Applications: it is used to calculate the limiting molar conductivity of weak electrolytes (which cannot be found by extrapolation) and the degree of dissociation of a weak electrolyte.
Marking-scheme points
- ✓At infinite dilution, molar conductivity = sum of ionic contributions
- ✓Ions migrate independently
- ✓Used to find limiting molar conductivity of weak electrolytes and degree of dissociation
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Electrochemistry
State Faraday's two laws of electrolysis.
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Faraday's first law states that the mass of a substance deposited or liberated at an electrode during electrolysis is directly proportional to the quantity of electric charge passed through the electrolyte (m is proportional to Q = I t). Faraday's second law states that when the same quantity of charge is passed through different electrolytes, the masses of substances deposited or liberated are directly proportional to their chemical equivalent weights.
m proportional to Q = I t
Marking-scheme points
- ✓First law: mass deposited is proportional to charge passed (m proportional to It)
- ✓Second law: for same charge, mass is proportional to equivalent weight
- ✓One Faraday (96500 C) deposits one gram equivalent
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Electrochemistry
A current of 5 A is passed through a silver nitrate solution for 30 minutes. Calculate the mass of silver deposited. (Atomic mass of Ag = 108, F = 96500 C/mol)
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Charge passed Q = I t = 5 x (30 x 60) = 5 x 1800 = 9000 C. Silver is deposited by Ag+ + e- -> Ag, so 1 mole of electrons (96500 C) deposits 108 g of silver. Mass of Ag = (108/96500) x 9000 = (108 x 9000)/96500 = 972000/96500 = 10.07 g.
mass = (equivalent mass x Q)/96500
Marking-scheme points
- ✓Q = I t = 5 x 1800 = 9000 C
- ✓96500 C deposits 108 g of Ag (Ag+ + e- -> Ag)
- ✓Mass = (108 x 9000)/96500 = 10.07 g
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Electrochemistry
Distinguish between primary and secondary cells with one example each.
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Chemical Kinetics
Define the rate of a chemical reaction. Distinguish between average and instantaneous rate.
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Chemical Kinetics
State the factors that affect the rate of a chemical reaction.
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Chemical Kinetics
Distinguish between order and molecularity of a reaction.
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Chemical Kinetics
Derive the integrated rate equation for a first order reaction.
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Chemical Kinetics
The rate constant of a first order reaction is 6.93 x 10^-3 s^-1. Calculate its half-life.
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Chemical Kinetics
Write the Arrhenius equation and define activation energy.
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Chemical Kinetics
How does a catalyst increase the rate of a reaction?
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Chemical Kinetics
Write the units of the rate constant for a zero order and a first order reaction.
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The p-Block Elements
Name the elements of Group 15 and give their general valence shell electronic configuration and common oxidation states.
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The p-Block Elements
Why does ammonia act as a Lewis base and have a higher boiling point than phosphine (PH3)?
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The p-Block Elements
Describe the Haber process for the manufacture of ammonia.
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The p-Block Elements
Describe the Ostwald process for the manufacture of nitric acid.
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The p-Block Elements
Distinguish between white phosphorus and red phosphorus.
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The p-Block Elements
How is ozone prepared? Why does it act as a powerful oxidising agent?
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The p-Block Elements
Describe the Contact process for the manufacture of sulphuric acid.
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The p-Block Elements
Why is fluorine the strongest oxidising agent among the halogens, and why does chlorine act as a bleaching agent?
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