Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questionsModel answersMarking-scheme pointsEvery chapterCBSE · ISC · State boards

483 questions · clear filters

PhysicsClass 122 marksmedium

Electrostatic Potential and Capacitance

Write the expression for the energy stored in a charged capacitor in three equivalent forms.

Reveal model answer + marking points

The energy stored in a charged capacitor is the work done in charging it. It can be written in three equivalent forms: U = (1/2) C V^2 = (1/2) Q V = Q^2/(2C), where C is the capacitance, Q the charge and V the potential difference. This energy is stored in the electric field between the plates.

U = (1/2) C V^2 = (1/2) QV = Q^2/(2C)

Marking-scheme points

  • U = (1/2) C V^2
  • U = (1/2) Q V = Q^2/(2C)
  • Energy stored in the electric field between plates
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Electrostatic Potential and Capacitance

How does the introduction of a dielectric slab between the plates of a capacitor affect its capacitance? Explain.

Reveal model answer + marking points

When a dielectric of dielectric constant K is fully inserted between the plates, the capacitance increases K times: C = K C0, where C0 is the capacitance with air. This is because the dielectric gets polarised and sets up an internal field opposite to the applied field, reducing the net field and hence the potential difference for the same charge; since C = Q/V, a smaller V means a larger C.

C = K C0

Marking-scheme points

  • Dielectric increases capacitance: C = K C0
  • Dielectric polarises and reduces the net field
  • Lower V for same Q -> higher C
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Current Electricity

State Ohm's law. Define resistance and give its SI unit.

Reveal model answer + marking points

Ohm's law states that, at constant temperature, the current flowing through a conductor is directly proportional to the potential difference across its ends, so V = IR, where R is a constant called the resistance. Resistance is the opposition offered by a conductor to the flow of current and is defined as R = V/I. Its SI unit is the ohm.

V = IR

Marking-scheme points

  • At constant temperature, V is proportional to I (V = IR)
  • Resistance R = V/I = opposition to current
  • SI unit: ohm
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Current Electricity

Define resistivity of a material. How does the resistance of a wire depend on its length and area of cross-section?

Reveal model answer + marking points

Resistivity (specific resistance) is the resistance of a conductor of unit length and unit area of cross-section; it depends on the material and temperature but not on its dimensions. The resistance of a wire is R = rho L/A, so it is directly proportional to its length L and inversely proportional to its area of cross-section A. The SI unit of resistivity is the ohm metre.

R = rho L/A

Marking-scheme points

  • Resistivity = resistance of unit length and unit area
  • R = rho L/A
  • R is proportional to L and inversely proportional to A
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Current Electricity

State Kirchhoff's two laws for electrical circuits.

Reveal model answer + marking points

Kirchhoff's junction (current) law states that the algebraic sum of currents meeting at a junction is zero, that is, the total current entering a junction equals the total current leaving it; it is based on conservation of charge. Kirchhoff's loop (voltage) law states that the algebraic sum of the changes in potential around any closed loop of a circuit is zero; it is based on conservation of energy.

sum(I) at junction = 0; sum(V) around loop = 0

Marking-scheme points

  • Junction law: sum of currents at a junction = 0 (charge conservation)
  • Loop law: sum of potential changes around a loop = 0 (energy conservation)
  • Used to analyse complex circuits
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Current Electricity

Write the effective emf and internal resistance when n identical cells are connected in series.

Reveal model answer + marking points

When n identical cells, each of emf E and internal resistance r, are connected in series (all in the same direction), the effective emf is n E and the total internal resistance is n r. The current through an external resistance R is I = n E/(R + n r). Series grouping is advantageous when the external resistance is much larger than the internal resistance.

I = nE/(R + nr)

Marking-scheme points

  • Series: effective emf = nE, internal resistance = nr
  • Current I = nE/(R + nr)
  • Useful when external R is much greater than internal r
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Current Electricity

How does the resistance of a metallic conductor vary with temperature? Write the relevant relation.

Reveal model answer + marking points

The resistance of a metallic conductor increases with a rise in temperature, because increased thermal motion of the atoms causes more frequent collisions of electrons, increasing the resistance. The relation is R(t) = R0 (1 + alpha (delta T)), where R0 is the resistance at the reference temperature, alpha is the temperature coefficient of resistance and delta T is the rise in temperature.

R = R0 (1 + alpha delta T)

Marking-scheme points

  • Resistance of a metal increases with temperature
  • More atomic vibration -> more electron collisions
  • R = R0 (1 + alpha delta T)
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Moving Charges and Magnetism

Write the expression for the magnetic Lorentz force on a charge moving in a magnetic field. When is it maximum and when zero?

Reveal model answer + marking points

A charge q moving with velocity v in a magnetic field B experiences a magnetic force F = q v B sin theta, where theta is the angle between v and B; in vector form F = q(v x B). The force is maximum (F = qvB) when the charge moves perpendicular to the field (theta = 90 deg), and it is zero when the charge moves parallel or antiparallel to the field (theta = 0 or 180 deg). The force is always perpendicular to the velocity, so it does no work.

F = q v B sin theta

Marking-scheme points

  • F = q v B sin theta = q(v x B)
  • Maximum (qvB) when v perpendicular to B
  • Zero when v parallel to B; force does no work
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Moving Charges and Magnetism

State the Biot-Savart law for the magnetic field due to a current element.

Reveal model answer + marking points

The Biot-Savart law states that the magnetic field dB due to a small current element I dl at a point P at distance r is directly proportional to the current I, the length dl and the sine of the angle theta between the element and the line joining it to P, and inversely proportional to the square of the distance r. Mathematically, dB = (mu0/4 pi) (I dl sin theta)/r^2, and its direction is perpendicular to the plane containing dl and r.

dB = (mu0/4 pi)(I dl sin theta)/r^2

Marking-scheme points

  • dB proportional to I dl sin theta and to 1/r^2
  • dB = (mu0/4 pi)(I dl sin theta)/r^2
  • Direction perpendicular to plane of dl and r
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Moving Charges and Magnetism

Write the expression for the force per unit length between two long parallel current-carrying wires and use it to define the ampere.

Reveal model answer + marking points

Two long parallel wires separated by distance d carrying currents I1 and I2 experience a force per unit length F/L = (mu0 I1 I2)/(2 pi d); the force is attractive if the currents are in the same direction and repulsive if opposite. The ampere is defined as that steady current which, when maintained in two infinitely long parallel wires of negligible cross-section placed 1 metre apart in vacuum, produces a force of 2 x 10^-7 newton per metre of length between them.

F/L = mu0 I1 I2/(2 pi d)

Marking-scheme points

  • F/L = mu0 I1 I2/(2 pi d)
  • Same direction currents attract, opposite repel
  • 1 ampere gives 2 x 10^-7 N/m between wires 1 m apart
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Magnetism and Matter

Write the expression for the magnetic dipole moment of a current-carrying loop. State its SI unit.

Reveal model answer + marking points

A current loop behaves as a magnetic dipole. The magnetic dipole moment of a coil of N turns each of area A carrying current I is m = N I A, and it is directed perpendicular to the plane of the loop (given by the right-hand rule). Its SI unit is ampere metre squared (A m^2). The torque on it in a field B is m x B.

m = N I A

Marking-scheme points

  • Magnetic moment m = N I A
  • Directed perpendicular to the plane of the loop
  • SI unit: ampere metre squared (A m^2)
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Magnetism and Matter

Distinguish between diamagnetic, paramagnetic and ferromagnetic substances with one example each.

Reveal model answer + marking points

Diamagnetic substances are weakly repelled by a magnetic field and move from stronger to weaker regions; they have a small negative susceptibility (e.g. bismuth, copper). Paramagnetic substances are weakly attracted by a magnetic field and have a small positive susceptibility (e.g. aluminium, sodium). Ferromagnetic substances are strongly attracted and can be permanently magnetised; they have a large positive susceptibility (e.g. iron, cobalt, nickel).

Marking-scheme points

  • Diamagnetic: weakly repelled, small negative susceptibility (bismuth)
  • Paramagnetic: weakly attracted, small positive susceptibility (aluminium)
  • Ferromagnetic: strongly attracted, large positive susceptibility (iron)
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Magnetism and Matter

State any four properties of magnetic field lines.

Reveal model answer + marking points

(1) Magnetic field lines are continuous closed curves that pass from the south to the north pole inside the magnet and from the north to the south pole outside it. (2) The tangent drawn at any point on a field line gives the direction of the magnetic field at that point. (3) Two field lines never intersect each other (as the field can have only one direction at a point). (4) The lines are crowded where the field is strong and spread apart where it is weak.

Marking-scheme points

  • Continuous closed loops (S to N inside, N to S outside)
  • Tangent gives field direction; no two lines intersect
  • Crowded where field is strong
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Magnetism and Matter

Define magnetic susceptibility and relative permeability. Write the relation between them.

Reveal model answer + marking points

Magnetic susceptibility (chi) is the ratio of the intensity of magnetisation (M) produced in a material to the magnetising field (H): chi = M/H; it measures how easily a material can be magnetised. Relative permeability (mu_r) is the ratio of the permeability of the material to that of free space. The relation between them is mu_r = 1 + chi.

mu_r = 1 + chi

Marking-scheme points

  • Susceptibility chi = M/H (ease of magnetisation)
  • Relative permeability mu_r = mu/mu0
  • Relation: mu_r = 1 + chi
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Electromagnetic Induction

State Faraday's laws of electromagnetic induction.

Reveal model answer + marking points

Faraday's first law states that whenever the magnetic flux linked with a closed circuit changes, an emf is induced in the circuit, and it lasts as long as the flux is changing. Faraday's second law states that the magnitude of the induced emf is equal to the rate of change of magnetic flux linked with the circuit: e = -N (d(flux)/dt), where N is the number of turns. The negative sign is due to Lenz's law.

e = -N d(flux)/dt

Marking-scheme points

  • Changing magnetic flux induces an emf
  • Induced emf = rate of change of flux: e = -N d(flux)/dt
  • Negative sign from Lenz's law
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Electromagnetic Induction

State Lenz's law. Which conservation principle does it represent?

Reveal model answer + marking points

Lenz's law states that the direction of the induced current (or emf) is always such that it opposes the change in magnetic flux that produces it. For example, if a magnet is pushed towards a coil, the induced current opposes its approach. Lenz's law is a consequence of the law of conservation of energy, because work has to be done against the opposing force, and this work appears as electrical energy.

Marking-scheme points

  • Induced current opposes the change in flux causing it
  • Gives the direction of the induced current
  • Consequence of conservation of energy
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Electromagnetic Induction

Define self-inductance of a coil. State its SI unit.

Reveal model answer + marking points

Self-inductance is the property of a coil by virtue of which it opposes any change in the current flowing through it, by inducing an opposing emf (back emf). It is defined as the flux linkage per unit current (N flux = L I) or from the induced emf e = -L (dI/dt), where L is the self-inductance. Its SI unit is the henry (H).

e = -L dI/dt

Marking-scheme points

  • Coil opposes change in its own current (back emf)
  • N flux = L I, or e = -L dI/dt
  • SI unit: henry (H)
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Electromagnetic Induction

Define mutual inductance between two coils. On what factors does it depend?

Reveal model answer + marking points

Mutual inductance is the property by which a change of current in one coil (primary) induces an emf in a neighbouring coil (secondary) due to the change in flux linkage. It is defined by e2 = -M (dI1/dt), where M is the mutual inductance, whose SI unit is the henry. It depends on the number of turns of the coils, their geometry (area and length), the distance and orientation between them, and the permeability of the core material.

e2 = -M dI1/dt

Marking-scheme points

  • Change of current in one coil induces emf in another
  • e2 = -M dI1/dt (SI unit henry)
  • Depends on turns, geometry, separation and core material
Still unsure? Ask the AI tutor →
PhysicsClass 122 marksmedium

Electromagnetic Induction

What are eddy currents? State two applications.

Reveal model answer + marking points

Eddy currents are the circulating induced currents produced in the body of a conductor when the magnetic flux linked with it changes. They flow in closed loops within the conductor and generally cause heating and energy loss. Applications: they are used in induction furnaces (to melt metals by the heat produced), in electromagnetic braking of trains, in electric (induction) meters, and in induction cooktops. Laminating the cores of transformers reduces energy loss due to eddy currents.

Marking-scheme points

  • Circulating induced currents in a conductor due to changing flux
  • Cause heating and energy loss
  • Applications: induction furnace, electromagnetic braking, induction cooktop
Still unsure? Ask the AI tutor →
PhysicsClass 122 markseasy

Alternating Current

Define the root mean square (RMS) value of alternating current. Write its relation with the peak value.

Reveal model answer + marking points

The RMS (root mean square) value of an alternating current is that value of steady direct current which produces the same heating effect in a given resistance in the same time as the alternating current does. For a sinusoidal current of peak value I0, the RMS value is Irms = I0/sqrt(2) = 0.707 I0. Similarly Vrms = V0/sqrt(2). AC meters read RMS values.

Irms = I0/sqrt(2)

Marking-scheme points

  • RMS = equivalent DC giving the same heating effect
  • Irms = I0/sqrt(2) = 0.707 I0
  • Vrms = V0/sqrt(2); AC meters read RMS
Still unsure? Ask the AI tutor →
← PrevPage 12 of 25Next →

You are more ready than you feel.

One question at a time is how every topper started. Bookmark this, revise a few each day, and watch the fear shrink. And if a friend is stressing about boards — send this their way. You both win.